Violent solution to the question of guessing the ranking

5 Three athletes took part in 10 Meter diving competition , They were asked to predict the outcome of the game ：

A Said the player ：B second , My third ;

B Said the player ： I'm second ,E Fourth ;

C Said the player ： I'm number one ,D second ;

D Said the player ：C Last , My third ;

E Said the player ： My fourth ,A First of all ;

After the game , Each player is half right , Please program to determine the position of the competition .

From the title, we can see , The problem has only one solution , also A,B,C,D,E The ranking of is divided into 1,2,3,4,5.

Then we might as well design five cycles , The variable for each cycle is set to A,B,C,D,E.

Let them each cycle 5 Take out all possible cases at once .

Add the judgment condition in the question at the end .

Pay attention here ： Every condition of everyone must be judged , So use logical or “||” no

Because if logic is applied, there may be a non unique solution .

Since everyone's condition is one true and one false , Then we might as well design such a judgment ：

（B == 2）+（A == 3）== 1

In this way, there is judgment on both sides , Next is the implementation of the code

#include <stdio.h>
int main()
{
	int A, B, C, D, E;
	for (A = 1; A <= 5; A++)
	{
		for (B = 1; B <= 5; B++)
		{
			for (C = 1; C <= 5; C++)
			{
				for (D = 1; D <= 5; D++)
				{
					for (E = 1; E <= 5; E++)
					{
						if ((B == 2) + (A == 3) == 1 &&
							(B == 2) + (E == 4) == 1 &&
							(C == 1) + (D == 2) == 1 &&
							(C == 5) + (D == 3) == 1 &&
							(E == 4) + (A == 1) == 1 &&
							A * B * C * D * E == 120)
						{
							printf("A = %d,B = %d,C = %d,D = %d,E = %d\n", A, B, C, D, E);
						}
					}
				}
			}
		}
	}
	return 0;
}

  The result is A = 3,B = 1,C = 5,D = 2,E = 4.