[introduction to C language] zzulioj 1026-1030

ZZULIOJ 1026: Character type judgment

Title Description

Enter a character from the keyboard , Determine whether the character is capitalized 、 Lowercase letters 、 Numeric characters or other characters . Output corresponding prompt information respectively .

Input

Enter a character .

Output

If the character is a capital letter , The output “upper”; If it's lowercase , The output “lower”; If it is a numeric character , The output “digit”; For other characters , The output “other”.（ The output does not contain double quotes ）.

The sample input  

E

Sample output  

upper

#include<stdio.h>#include<ctype.h>
int main(){
       char ch;    scanf("%c",&ch);    if(islower(ch))        printf("lower\n");    else if(isupper(ch))        printf("upper\n");    else if(isdigit(ch))        printf("digit\n");    else        printf("other\n");    return 0;}

ZZULIOJ 1027: Judge the number of daffodils

Title Description

Spring is the season of flowers , Narcissus is one of the most charming representatives , There's a narcissus number in math , He defines it like this ：“ Narcissistic number ” A three digit number , The cube sum of its digits is equal to itself , such as ：153=13+53+33.  Now ask for a three digit number , Judge whether the number is daffodil number , If it is , Output “yes”, Otherwise output “no” 

Input

Enter a positive three digit integer .

Output

Output “yes” or “no”.

The sample input  

153

Sample output  

yes

#include <stdio.h>#include <stdlib.h> int main(){   int m,a,b,c;    scanf ("%d",&m);    a=m/100;    b=(m/10)%10;    c=m%10;    if(m==a*a*a+b*b*b+c*c*c){
           printf("yes");    }    else{
           printf("no");    }    return 0;}

ZZULIOJ 1028:I love Leap year ！

Title Description

  According to a year , Determine if it's a leap year .

Input

  Enter as an integer , Represents a year .

Output

If it's a leap year , Output "Yes", Otherwise output "No". The output is on a single line .

The sample input  

2012

Sample output  

Yes

#include <stdio.h>#include <stdlib.h>  int main(){
         int y;    scanf("%d",&y);    if(y%400==0||(y%4==0&&y%100!=0)){
       printf("Yes\n");}    else    {
           printf("No\n");    }    return 0;}

ZZULIOJ 1029: Triangle determination

Title Description

Here are three positive integers , Judge whether using these three integers as the side length can form a triangle .

Input

The input is three int The positive integer of the range , There is a space between .

Output

If you can form a triangle , Output "Yes", Otherwise output "No"

The sample input  

3 4 5

Sample output  

Yes

#include <stdio.h>#include <stdlib.h>#include <math.h>
int main(){
       int a,b,c;    scanf("%d %d %d",&a,&b,&c);if(a+b>c&&a+c>b&&b+c>a){
       printf("Yes");}else    printf("No");     return 0;}

ZZULIOJ 1030: Judge right triangle

Title Description

Enter three positive integers , Judge whether using these three integers as the side length can form a right triangle .

Input

Enter three positive integers .

Output

Whether it can form a right triangle . If you can output ：yes. If not , Output ：no.

The sample input  

6 8 10

Sample output  

yes

#include <stdio.h>#include <stdlib.h>
int main(){
       int a,b,c;    scanf("%d%d%d",&a,&b,&c);if(a*a+b*b==c*c||a*a+c*c==b*b||b*b+c*c==a*a){
       printf("yes");}else    printf("no");    return 0;}