C language antithesis: who is the murderer!

The complete code is at the end!

Title description

A murder case occurred somewhere in Japan, and the police determined that the murderer must be one of four suspects through investigation.

The following are the confessions of the four suspects:

A said: Not me.

B said: yes C.

C said: yes D.

D said: C is talking nonsense

3 people are known to tell the truth and 1 person to tell the truth.

Now, based on this information, write a program to determine who the killer is.

Solution ideas

In this question, only one person told a lie and 3 people told the truth. We can return 1 for each time the truth is judged. Three times the truth is three 1s equal to 3. We can use each time to assume that a certain person is the murdererto judge whether what everyone said is the truth.So use the for statement to go from the murderer a to the murderer d, and each judgment is ok

Complete code

#includeint main(){char m;for (char i = 'a'; i <= 'd'; i++){if ((i != 'a') + (i == 'c') + (i == 'd') + (i != 'd') == 3){printf("%c", i);}}return 0;}