idea 方法注释：自定义修改method的return和params，void不显示

    /** 演示有参数返回void
     * <p>
     *
     * </p>
     *  
     * @param a a 
     * @param b b  
     * @author hk2018 
     * @since 2020/5/21 
     */
    public void x(int a, String b){
        System.out.println("dd");
    }


    /** 演示无参数返回void
     * <p>
     *
     * </p>
     *   
     * @author hk2018 
     * @since 2020/5/21 
     */
    public void x1(){
        System.out.println("dd");
    }

** 
 * <p>
 *
 * </p>
 * $param$$returns$ 
 * @author hk2018 
 * @since $date$ 
 */

下面为脚本

groovyScript("def result=' \\n'; def params=\"${_1}\".replaceAll('[\\\\[|\\\\]|\\\\s]', '').split(',').toList(); for(i = 0; i < params.size(); i++) {if(params[i] == '') return ''; result+=' * @param ' + params[i] + ' ' + params[i] + ((i < params.size() - 1) ? ' \\n' : '')}; return result", methodParameters()) 

returns脚本

groovyScript("if(\"${_1}\" == 'void') {return ;} else { def returnType = \"${_1}\"; def result = ' @return: ' + returnType; return result;}", methodReturnType());