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Class. Forname connection MySQL driver keeps throwing classnotfoundexception exception solution

2022-06-12 10:26:00 【Zi Jiao】


Class.forName Connect mysql Drive keeps throwing ClassNotFoundException abnormal , The solution is as follows ：

One 、 take  mysql-connector-java-5.1.47.jar Copied to the WebContent\WEB-INF\lib Directory . as follows ：
  C:\Software\java\workspaces\web1\myweb1\WebContent\WEB-INF\lib\mysql-connector-java-5.1.47.jar
  
Two 、 Right click on the item - Properties - Java Build Path - Libraries - Add JARs - JAR Selection - 
      find  mysql-connector-java-5.1.47.jar - OK - Apply - OK

3、 ... and 、 Connect MySQL normal , All the following codes . 

​
<%@ page language="java" contentType="text/html; charset=utf-8" pageEncoding="utf-8"%>
<%@ page import="java.sql.*" %>
<!DOCTYPE html>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<title>Insert title here</title>
</head>
<body>

<table border="1">
<% 
String url = "jdbc:mysql://127.0.0.1:3306/mysqldbname?useUnicode=true&characterEncoding=utf8";
String user = "root";
String password = "root";
try{
	Class.forName("com.mysql.jdbc.Driver");
	
	Connection con = DriverManager.getConnection(url,user,password);
	if ( con.isClosed() ) {
		out.println(  "failed to connect the database");
		return;
	}
	Statement statement = con.createStatement();
	String sql = "SELECT * FROM `users`";
	ResultSet rs = statement.executeQuery(sql);
	
	String category = null;
       String id = null;
       String name = null;
       String value = null;
       while( rs.next() ){
       	category = rs.getString("category");
           id = rs.getString("id");
           name = rs.getString("name");
           value = rs.getString("value");
           out.println("<tr>");
           out.println("<td>" + id + "</td>");
           out.println("<td>" + name + "</td>");
           out.println("<td>" + value + "</td>");
           out.println("<td>" + category + "</td>");
           out.println("</tr>");
       }
       
	rs.close();
	con.close();
	out.println( "succeeded connecting to the database");
}catch(SQLException e){
	e.printStackTrace();
}
%>
</table>
</body>
</html>

 

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本文为[Zi Jiao]所创，转载请带上原文链接，感谢
https://yzsam.com/2022/03/202203010525125666.html

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