Why does the JVM heap memory exceed 32g and pointer compression fail?

OOP The compressed size is four bytes , The largest addressing space of four bytes is 2^32 That is to say 4 individual G, Then the object size is 8 Integer multiples of bytes , Therefore, according to this feature, we only need to locate 8 Of bytes 1 One byte space can locate the object , therefore OOP The compressed address space is 2^32*8 Namely 32G, If the heap memory exceeds 32G It may cause that there is no way to use the compressed OOP Address , Therefore, the heap memory exceeds 32G Pointer compression will fail .