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Work arrangement of generator set
2022-07-25 02:27:00 【Touch the sun with your feet】
some Electric power The system uses four different types of generators to meet the power demand . The known power demand of each time of day is shown in table 1.
surface 1: Daily electricity demand ( mw ,MW)
time interval (0-24) | 0-5 | 5-7 | 7-10 | 10-13 | 13-17 | 17-20 | 20-22 | 22-24 |
demand | 10000 | 20000 | 24000 | 32000 | 25000 | 26000 | 15000 | 12000 |
Each generator has a maximum generating capacity , When connected to the power grid , Its output power should not be lower than a certain minimum output power . All generators have a starting cost , And the fixed hourly cost of working in the minimum power state , And if the power is higher than the minimum power , Then there is a cost per megawatt per hour for the excess power , Marginal cost . These data are listed in table 2 in .
surface 2: Generator condition
Quantity available | Minimum output power (MW) | Maximum output (MW) | fixed cost ( element / Hours ) | Marginal cost per megawatt ( element / Hours ) | start-up cost | |
model 1 | 10 | 800 | 1800 | 2200 | 2.7 | 4000 |
model 2 | 5 | 1000 | 1500 | 1800 | 2.2 | 1600 |
model 3 | 8 | 1200 | 2000 | 3800 | 1.8 | 2400 |
model 4 | 4 | 1800 | 3500 | 4600 | 3.6 | 1200 |
It is only allowed to start or shut down the generator at the beginning of each period . Different from starting the generator , It doesn't cost anything to shut down the generator .
problem (1) Which generators should be used in each period to minimize the total cost per day , What is the minimum total cost ?
problem (2) If at any time , The generator set in operation must be reserved 20% Generating capacity margin , In case of a sudden rise in electricity consumption . Then which generators should be used in each period to minimize the total cost per day , At this time, what is the minimum total cost ?
Choose to do :( Finished the question (1) And questions (2) And students who have spare power to learn, please continue )
problem (3) If the power demand in each period of the day is in the table 1 On the basis of 30% Left and right fluctuations , And the system has no energy storage . At this time, according to problem (1) Power generation plan , There are two possible situations :
1) System loss of load ( That is, the power demand is greater than the power generation ),
2) Power generation is greater than demand , Cause power waste .
Assume that the loss of load loss is q( Company : element / mw ), hypothesis q Value respectively q=600 and q=5000 Then how should the generator set be arranged to generate electricity in each period ?
The current topic is , Blogger micro signal 15090103612.
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