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20211104 为什么相似矩阵的迹相同
2022-06-13 08:55:00 【我起个什么名字呢】
设 A = ( a i j ) m × n , B = ( b i j ) n × m \boldsymbol{A}=\left(a_{i j}\right)_{m \times n}, \boldsymbol{B}=\left(b_{i j}\right)_{n \times m} A=(aij)m×n,B=(bij)n×m, 则 tr ( A B ) = tr ( B A ) \operatorname{tr}(\boldsymbol{A B})=\operatorname{tr}(\boldsymbol{B A}) tr(AB)=tr(BA);
则知道 P \boldsymbol{P} P是非奇异矩阵
tr ( B ) = tr ( P − 1 A P ) = tr ( A P P − 1 ) = tr ( A ) \operatorname{tr}(\boldsymbol{B})=\operatorname{tr}\left(\boldsymbol{P}^{-1} \boldsymbol{A} \boldsymbol{P}\right)=\operatorname{tr}\left(\boldsymbol{A P P}^{-1}\right)=\operatorname{tr}(\boldsymbol{A}) tr(B)=tr(P−1AP)=tr(APP−1)=tr(A)
多提一句, A B \boldsymbol{A B} AB和 B A \boldsymbol{BA} BA的非零特征值相同,证明过程如下
https://blog.csdn.net/Europe233/article/details/86727078
另外,相似矩阵的特征值相同
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