Basic use of array -- traverse the circular array to find the maximum value, minimum value, maximum subscript and minimum subscript of the array

Traverse the circular array to find the maximum value of the array , Minimum and maximum subscripts , Minimum subscript

package com.qy151.test5;

import java.util.Scanner;

/**
 * @unthor : YSH
 * @date : 11:10 2022/6/20
 */
public class Test6 {
    public static void main(String[] args) {
        // Get the maximum . And the subscript of the maximum 
        // Get the minimum , And the subscript of the minimum value 
        int[] nums={45,32,12,67,89,56,99,23,2,65};
        //           0  1  2  3  4  5  6  7 8  9


        // Output the maximum value through the subscript of the maximum value 
        // Output the minimum value through the subscript of the minimum value 
        //System.out.println(nums[4]);
        //System.out.println(nums[2]);

        // Define the maximum position 
        int maxPos=0;
        // Define the minimum position 
        int minPos=0;


        for (int i=1;i<nums.length;i++){
            // Get data by subscript , Compare 
            // Compare the data in the corresponding position 
            if (nums[maxPos]<nums[i]){
                // Where to record data 
                maxPos=i;
            }
            // If the data corresponding to the lowest subscript is not the smallest , At this time, the minimum subscript is used to store the traversed subscript data 
            if (nums[minPos]>nums[i]){
                // Save subscript 
                minPos=i;
            }
        }
        System.out.println(" The subscript of the maximum value :"+maxPos+" The corresponding maximum value :"+nums[maxPos]);
        System.out.println(" Subscript of minimum value :"+minPos+" The corresponding minimum value :"+nums[minPos]);
    }
}