"Daily practice, happy water" 1108 IP address invalidation

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Try to catch up with the original question ：

1108. IP Address invalidation

* A brief introduction to the topic ：

Give you an effective IPv4 Address address, Go back to this IP Invalid version of address .

The so-called invalidation IP Address , In fact, it is to use “[.]” Instead of every “.”.

* Their thinking ：

1. Simulation Dafa is good
2. Traversal string , hold . Replace with [.] that will do
3. over

*C++ Code ：

class Solution {
    
public:
    string defangIPaddr(string address) {
    
        string ans;
        for (auto  c : address) {
    
            if (c == '.') {
    
                ans += "[.]";
            } else {
    
                ans.push_back(c);
            }
        }
        return ans;
    }
};

Result display ：