[C language practice - printing square and its deformation]

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Preface

A square is a special parallelogram , See Baidu Encyclopedia for the definition

This article is mainly about writing diamond exercises , Print diamonds on the screen .

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1、 Print graphics 1

// Print squares and their deformations 
int main()
{
    
	int n = 0;
	scanf("%d", &n);
	for (int i = 0; i < n; i++)// Row number 
	{
    
		for (int j = 0; j < n; j++)// Number of columns 
		{
    
			printf("*");
		}
		printf("\n");
	}
	return 0;
}

The results are as follows , Although it is 10 That's ok 10 Column , Because there is no space between characters in the same line , And between different lines due to line breaks , The printed graphic does not look square , It's a rectangle ：

2、 Print graphics 2

// Print squares and their deformations 
int main()
{
    
	int n = 0;
	scanf("%d", &n);
	for (int i = 0; i < n; i++)// Row number 
	{
    
		for (int j = 0; j < n; j++)// Number of columns 
		{
    
			printf("* ");
		}
		printf("\n");
	}
	return 0;
}

The results are as follows , It looks more like a square , But in fact, it is related to graphics 1 It is one thing .

3、 Print graphics 3

Print a square , rotate 45 degree

// Print a square , rotate 45 degree , No blank space version 
int main()
{
    
	int n = 0;
	scanf("%d", &n);
	// Print the top half  n
	for (int i = 0; i < n; i++)
	{
    
		// Print a row 
		// Print space 
		int j = 0;
		for (j = 0; j < n - 1 - i; j++)
		{
    
			printf(" ");
		}
		// Print *
		for (j = 0; j < 2 * i + 1; j++)
		{
    
			printf("*");
		}
		printf("\n");
	}
	// Print the bottom half  n-1
	for (int i = 0; i < n - 1; i++)
	{
    
		// Print a row 
		// Print space 
		int j = 0;
		for (j = 0; j <= i; j++)
		{
    
			printf(" ");
		}
		// Print *
		for (j = 0; j < (n - 1 - i) * 2 - 1; j++)
		{
    
			printf("*");
		}
		printf("\n");
	}
	return 0;
}

** The results are as follows ,** It is still due to the inconsistent spacing of rows and columns , The square becomes a diamond ：

4、 Print graphics 4

// Print a square , rotate 45 degree , Blank version 
int main()
{
    
	int n = 0;
	scanf("%d", &n);
	// Print the top half  n
	for (int i = 0; i < n; i++)
	{
    
		// Print a row 
		// Print space 
		int j = 0;
		for (j = 0; j < n - 1 - i; j++)
		{
    
			printf(" ");
		}
		// Print *
		for (j = 0; j <= i; j++)
		{
    
			printf("* ");
		}
		printf("\n");
	}
	// Print the bottom half  n-1
	for (int i = 0; i < n - 1; i++)
	{
    
		// Print a row 
		// Print space 
		int j = 0;
		for (j = 0; j <= i; j++)
		{
    
			printf(" ");
		}
		// Print *
		for (j = 0; j <(n-1-i); j++)
		{
    
			printf("* ");
		}
		printf("\n");
	}
	return 0;
}

The results are as follows , The square is also a diamond , And graphics 3 The difference is whether there are spaces ：

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summary

This article exercises printing squares and their deformations , Mainly practice ：

• Outer loop 、 Application of internal circulation
• Pay attention to the number of lines 、 Space number 、 Symbol * The mathematical relationship between numbers

I didn't expect it before printing , The row and column intervals are different , The length and width of the square will be different . It can be seen that only the print results can verify whether the implementation results of your own code are consistent with your own ideas . The square became a combination of rectangle and diamond , I feel like I have written another article .