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Reverse linked list - head insertion inversion method
2022-07-30 22:55:00 【Knights of the code】
(1)思想:是指在原有链表的基础上,依次将位于链表头部的节点摘下,然后采用从头部插入的方式生成一个新链表,则此链表即为原链表的反转版.
(2)实现(如下图):
At first the creation of a new head node,然后在创建一个temp指针.
link * new_head = (link*)malloc(sizeof(link));
new_head->elem = 0;
new_head->next = NULL;
link * temp = NULL;
The next step will result in the node in the list:
temp = head->next;
//将 temp 从 head 中摘除
head->next = head->next->next;
For the new list of head insert:
//将 temp 插入到 new_head 的头部
temp->next = new_head->next;
new_head->next = temp;
以此类推:
摘除2:
temp = head->next;
head->next = head->next->next;
插入2:
temp->next = new_head->next;
new_head->next = temp;
插入完成:
摘除3:
插入3:
摘除4:
(Mark end of cycle)
插入4:
插入END.
片段代码:
//头插法反转链表
link * head_reverse(link * head) {
//Add the head for a new node
link * new_head = (link*)malloc(sizeof(link));
new_head->elem = 0;
new_head->next = NULL;
link * temp = NULL;
if (head == NULL || head->next == NULL || head->next->next == NULL ) {
return head;
}
while (head->next != NULL)
{
temp = head->next;
//将 temp 从 head 中摘除
head->next = head->next->next;
//将 temp 插入到 new_head 的头部
temp->next = new_head->next;
new_head->next = temp;
}
return new_head;
}
完整代码:
#include<stdio.h>
#include<stdlib.h>
typedef struct Link{
int elem;
struct Link* next;
}link;
link * initLink() {
int i = 0;
link * temp = NULL;
link * p = (link*)malloc(sizeof(link));//创建头节点
//首元节点先初始化
p->elem = 0;
p->next = NULL;
temp = p;//头指针指向头节点
for (i = 1; i < 5; i++) {
link *a = (link*)malloc(sizeof(link));
a->elem = i;
a->next = NULL;
temp->next = a;
temp = temp->next;
}
return p;
}
void display(link *p) {
link* temp = p->next;//将temp指针重新指向首元结点
//只要temp指针指向的结点的next不是Null,就执行输出语句.
while (temp) {
printf("%d ", temp->elem);
temp = temp->next;
}
printf("\n");
}
//头插法反转链表
link * head_reverse(link * head) {
//Add the head for a new node
link * new_head = (link*)malloc(sizeof(link));
new_head->elem = 0;
new_head->next = NULL;
link * temp = NULL;
if (head == NULL || head->next == NULL || head->next->next == NULL ) {
return head;
}
while (head->next != NULL)
{
temp = head->next;
//将 temp 从 head 中摘除
head->next = head->next->next;
//将 temp 插入到 new_head 的头部
temp->next = new_head->next;
new_head->next = temp;
}
return new_head;
}
int main()
{
link*p=initLink();
printf("原始链表:");
display(p);
printf("反转链表:");
p=head_reverse(p);
display(p);
return 0;
}
输出结果:
若无头结点:
代码片段:
//头插法反转链表
link * head_reverse(link * head) {
link * new_head = NULL;
link * temp = NULL;
if (head == NULL || head->next == NULL) {
return head;
}
while (head != NULL)
{
temp = head;
//将 temp 从 head 中摘除
head = head->next;
//将 temp 插入到 new_head 的头部
temp->next = new_head;
new_head = temp;
}
return new_head;
}
完整代码:
#include<stdio.h>
#include<stdlib.h>
typedef struct Link{
int elem;
struct Link* next;
}link;
link * initLink() {
int i;
link * p = NULL;//创建头指针
link * temp = (link*)malloc(sizeof(link));//创建首元节点
//首元节点先初始化
temp->elem = 1;
temp->next = NULL;
p = temp;//头指针指向首元节点
for (i = 2; i < 5; i++) {
link *a = (link*)malloc(sizeof(link));
a->elem = i;
a->next = NULL;
temp->next = a;
temp = temp->next;
}
return p;
}
void display(link *p) {
link* temp = p;//将temp指针重新指向头结点
//只要temp指针指向的结点的next不是Null,就执行输出语句.
while (temp) {
printf("%d ", temp->elem);
temp = temp->next;
}
printf("\n");
}
//头插法反转链表
link * head_reverse(link * head) {
link * new_head = NULL;
link * temp = NULL;
if (head == NULL || head->next == NULL) {
return head;
}
while (head != NULL)
{
temp = head;
//将 temp 从 head 中摘除
head = head->next;
//将 temp 插入到 new_head 的头部
temp->next = new_head;
new_head = temp;
}
return new_head;
}
int main()
{
link*p=initLink();
printf("原始链表:");
display(p);
printf("反转链表:");
p=head_reverse(p);
display(p);
return 0;
}
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