Electronic Society C language level 1 31. Calculate line segment length

Electronics Association C Language 1 level  31 、 Calculate the line length

OpenJudge - 16: Calculate the line length

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C++ Method 1 ：

/*
 Electronics Association  C Language  1 level   31 、  Calculate the line length 
http://noi.openjudge.cn/ch0103/16/

 The coordinates of the two endpoints of a given line segment  A（Xa,Ya）,B（Xb,Yb）, Find line segment  AB  The length of .
 There are two lines of input .
 The first line is two real numbers  Xa,Ya, namely  A  Coordinates of .
 The second line is two real numbers  Xb,Yb, namely  B  Coordinates of .
 The absolute value of all real numbers in the input does not exceed  10000.
 Output 
 A real number , That's line segments  AB  The length of , Keep it after the decimal point  3  position .
 The sample input 
1 1
2 2
 Sample output 
1.414

 The coordinates of the two endpoints of a given line segment  A（Xa,Ya）,B（Xb,Yb）, Find line segment  AB  The length of .
http://noi.openjudge.cn/ch0103/16/
*/
#include <bits/stdc++.h>
#include<iostream>
#include<cstdio>
#include<cmath>
using namespace std;
int main() 
{
	double xa,xb,ya,yb,len;

	cin>>xa>>ya;
	cin>>xb>>yb;
	
	len=sqrt( pow(xa-xb,2)+pow(ya-yb,2) );
	//len=sqrt(pow(2,xa-xb) +pow(2,ya-yb));
	//sqrt( ) Square root function  pow( ) power function 

	printf("%0.3f",len);

	return 0;
}

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C++ Method 2 ：

/*
 Electronics Association  C Language  1 level   31 、  Calculate the line length   Method 2  
http://noi.openjudge.cn/ch0103/16/
*/
#include <iostream>
#include <iomanip>
#include <cmath>
using namespace std;
int main()
{
    double Xa, Ya, Xb, Yb;
    
	cin >> Xa >> Ya >> Xb >> Yb;
    
	double ans;
    
	//ans=sqrt(pow((Xa-Xb),2)+pow((Ya-Yb),2));
    ans=sqrt( (Xa-Xb)*(Xa-Xb) + (Ya-Yb)*(Ya-Yb) );
    
	cout << fixed << setprecision(3) <<ans ;
    
	return 0;
}

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C＋＋ Method 3 ：

/*
 Electronics Association  C Language  1 level   31 、  Calculate the line length   Method 3  
http://noi.openjudge.cn/ch0103/16/
*/
#include <bits/stdc++.h>
#include <iostream>
using namespace std;

int main()
{
    double a,b,c,d;
    
	cin>>a>>b;
    
	cin>>c>>d;
    
	printf("%.3f\n",sqrt((a-c)*(a-c)+(b-d)*(b-d)));
    //printf("%.3f\n",sqrt((a-c)*(a-c)＋(b-d)*(b-d)));
    
	return 0;
}

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C＋＋ Method four ：

/*
 Electronics Association  C Language  1 level   31 、  Calculate the line length   Method four  
http://noi.openjudge.cn/ch0103/16/
*/
#include <math.h>
#include <stdlib.h>
int main()
{
    double Xa,Ya,Xb,Yb;
    double l;
    
    scanf("%lf%lf%lf%lf",&Xa,&Ya,&Xb,&Yb);
    
    l=sqrt((Xb-Xa)*(Xb-Xa)+(Yb-Ya)*(Yb-Ya));
    
    printf("%.3lf\n",l);
    
	system("pause");
	
	return 0;
}

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C＋＋　 Method five ：

/*
 Electronics Association  C Language  1 level   31 、  Calculate the line length   Method five  
http://noi.openjudge.cn/ch0103/16/
*/
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
	float xa,ya,xb,yb;
	
	scanf("%f%f%f%f",&xa,&ya,&xb,&yb);
	
	printf("%.3f\n",sqrt((xa-xb)*(xa-xb)+(ya-yb)*(ya-yb)));
	system("pause");
	return 0;
}

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python3 Code ：

"""
1.3 Arithmetic expression and sequential execution of programming basis  16  Calculate the line length 
http://noi.openjudge.cn/ch0103/16/
https://blog.csdn.net/weixin_45852964/article/details/103090884

"""
import math

xa,ya=map(float,input().split())

xb,yb=map(float,input().split())

l=math.sqrt((yb-ya)*(yb-ya)+(xb-xa)*(xb-xa))

print("%.3f"%l)

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