2022.06.26(LC_6100_统计放置房子的方式数)

方法：动态规划

 

class Solution {
    public int countHousePlacements(int n) {
        //状态：dp[i] 表示有i个地块时的放置房子方式数
        long[] dp = new long[n + 1];
        dp[0] = 1;
        dp[1] = 2;
        for (int i = 2; i <= n; i++) {
            dp[i] = (dp[i - 1] + dp[i - 2]) % 1000000007;
        }
        return (int)(dp[n] * dp[n] % 1000000007);
    }
}