c现代方法16章基础

练习题

6.

#include <stdio.h>
#include <stdlib.h>
struct time {
	int hours;
	int minutes;
	int seconds;
};
struct time split_time(long total_seconds)
{
	struct time ret;
	ret.hours = total_seconds / 3600;
	ret.minutes = (total_seconds - ret.hours * 3600) / 60;
	ret.seconds = total_seconds - ret.hours * 3600 - ret.minutes * 60;
	return ret;
}

int main()
{
	struct time t1 = split_time(10000);
	printf("hours: %ld minutes : %ld seconds : %ld\n",t1.hours,t1.minutes,t1.seconds);
	system("pause");
	   	  return 0;
}

运行结果如下： 

7.

#include <stdio.h>

struct fraction {

	int numerator; //分子
	int denominator;//分母

};


//为啥这个函数自己写出来，自己也貌有点不明白
int get_gcd(int m, int n)
{
	if (n == 0)
	{
		return m;
	}
	return get_gcd(n,m % n);
}

struct fraction 
	simplify_fraction(struct fraction * f)
{
	struct fraction ret;
	int gcd = get_gcd(f->numerator,f->denominator);
	ret.numerator = f->numerator / gcd;
	ret.denominator = f->denominator / gcd;
	return ret;
}

//（b）分数相加

struct fraction add(struct fraction * l,struct fraction * r)
{ 
	struct fraction ret;
	ret.numerator = l->numerator * r->denominator + l->denominator * r->numerator;
	ret.denominator = l->denominator * r->denominator;
	ret = simplify_fraction(&ret);
	return ret;
}

//(c)分数相减

struct fraction subtraction(struct fraction * l, struct fraction * r)

{
	struct fraction ret;
	ret.numerator = l->numerator * r->denominator - l->denominator * r->numerator;
	ret.denominator = l->denominator * r->denominator;
	ret = simplify_fraction(&ret);
	return ret;
}

//(d)把两个分数相乘
struct fraction multiply(struct fraction * l, struct fraction * r)

{
	struct fraction ret;
	ret.numerator = l->numerator * r->numerator;
	ret.denominator = l->denominator * r->denominator;
	ret = simplify_fraction(&ret);
	return ret;
}

//(e)除法 略（和乘法类似）


int main()
{
	//(a)
	struct fraction f1;
	f1.numerator = 1001;
	f1.denominator = -7;
	struct fraction sim_of_f1 = simplify_fraction(&f1);
	printf("numerator:%d ,denominator: %d\n",sim_of_f1.numerator,sim_of_f1.denominator);
	//(b)
	struct fraction f2,f3;
	f2.denominator = 3;
	f2.numerator = 4;
	f3.denominator = 5;
	f3.numerator = 6;
	struct fraction r2 = add(&f2,&f3);
	printf("nume:%d,deno:%d\n",r2.numerator,r2.denominator);

	//(c)
	struct fraction r3 = subtraction(&f2,&f3);
	printf("nume:%d,deno:%d\n", r3.numerator, r3.denominator);

	//(d)
	struct fraction r4 = multiply(&f2,&f3);
	printf("nume:%d,deno:%d\n", r4.numerator, r4.denominator);


	


	
	return 0;
}