水管工遊戲

問題描述

分析

代碼實現

#include <stdio.h>
	int n, m, front,top,flag;
	int a[51][51];
	int book[51][51];
struct note {
    
	int x;
	int y;
};
struct note s[101];
void dfs(int x,int y,int front) {
    
	int i;
	if (x == n && y == m + 1) {
    
			flag = 1;
		for (i = 0; i < top; i++) {
    
			
			printf("(%d,%d)", s[i].x, s[i].y);
		}
		printf("\n---------------------\n");
		return;
	}
	if (x<1 || x>n || y<1 || y>m)
		return;
	if (a[x][y] == 0)
		return;
	if (book[x][y] == 1)
		return;
	s[top].x = x;
	s[top].y = y;
	top++;
	book[x][y] = 1;
	//直管
	if (a[x][y] >= 5 ) {
    
		
		if (front == 1) {
    
			dfs(x , y+1, 1);
		}
		if (front == 2) {
    
			dfs(x+1, y , 2);
		}
		if (front == 3) {
    
			dfs(x, y - 1, 3);
		}
		if (front == 4) {
    
			dfs(x - 1, y, 4);
		}
	}
	if (a[x][y] <= 4 && a[x][y] >= 1 ) {
    
		
		if (front == 1) {
    
			dfs(x+1, y , 2);
			dfs(x - 1, y, 4);
		}
		if (front == 2) {
    
			dfs(x , y+1, 1);
			dfs(x , y-1, 3);
		}
		if (front == 3) {
    
			dfs(x-1, y , 4);
			dfs(x + 1, y, 2);
		}
		if (front == 4) {
    
			dfs(x , y+1, 1);
			dfs(x , y-1, 3);
		}
		
		
		
	}
	book[x][y] = 0;
	top--;
	return;
}
int main() {
    
	int i, j;
	scanf_s("%d %d", &n, &m);
	for (i = 1; i <= n; i++)
		for (j = 1; j <= m; j++)
			scanf_s("%d", &a[i][j]);
	
	dfs(1, 1, 1);
	if (flag == 0) {
    
		printf("找不到路徑。");
	}
	getchar(); getchar();
	return 0;
}

輸入

5 4
5 3 5 3
1 5 3 0
2 3 5 1
6 1 1 5
1 5 5 4

輸出（直接輸出路徑）

(1,1)(1,2)(2,2)(3,2)(3,3)(3,4)(4,4)(5,4)