Informatics Olympiad all in one 2059: [example 3.11] buy a pen

2059：【 example 3.11】 Buy a pen

The time limit : 1000 ms         Memory limit : 65536 KB
Submission number : 15417     Passing number : 8034

【 Title Description 】

The end of the term is coming , Squad leader Q It was decided that the rest of the class fee would be xx Yuan , It is used to buy several pens and reward some good learners 、 Good students . It is known that there are three kinds of pens in the store , Their unit price is 6 element 、5 Genna 4 element . Small Q Want to buy as many pens as possible （ Encourage as many students as possible ）, At the same time, he doesn't want to have any surplus money . Please make a program , Help small Q Work out a plan for buying pens .

【 Input 】

A positive integer xx（ The rest of the class fee ）.

【 Output 】

a line , In turn 6 element 、5 Genna 4 The number of yuan , Separated by a space .

【 sample input 】

10

【 sample output 】

1 0 1

If you want to buy the most pens, you must buy the cheapest ones （4 element ）, The set-up fee is x element , If x/4=0, That is, buy all 4 Yuan pen , if x/4=1, You can buy one less 4 Yuan to buy a pen 5 yuan , if x/4=2, Buy one less 4 Yuan's pen , Buy one 6 Yuan's pen , Empathy , if x/4=3, Buy less 2 only 4 Replace the yuan pen with one 5 A yuan pen 6 Yuan pen .

#include<iostream>
using namespace std;
int main()
{
	int x,a,b,c;
	cin >> x;
	if (x % 4 == 0)
	{
		a = 0;
		b = 0;
		c = x / 4;
	}
	else if (x % 4 == 1)
	{
		a = 0;
		b = 1;
		c = x / 4 - 1;
	}
	else if (x % 4 == 2)
	{
		a = 1;
		b = 0;
		c = x / 4 - 1;

	}
	else if (x % 4 == 3)
	{
		a = 1;
		b = 1;
		c = x / 4 - 2;
	}
	cout << a << " " << b << " " << c;
}