【LeetCode】53. Maximum subarray and

1. subject

2. thought

• dp[i] Said to nums[i] Maximum value obtained at the end
• The recursive formula ：dp[i+1] = max(dp[i],0)+ num[i+1]

3. Code

class Solution:
    def maxSubArray(self, nums: List[int]) -> int:
        dp = [0] * len(nums)
        dp[0] = nums[0]
        res = dp[0]
        for i in range(1,len(nums)):
            if dp[i-1]>0:
                dp[i] = dp[i-1] + nums[i]
            else:
                dp[i] = nums[i]
            res = max(res,dp[i])
        # print(dp)
        return res