Sqlalchemy - subquery in a where clause - Sqlalchemy - subquery in a where clause

problem ：

I've just recently started using SQLAlchemy and am still having trouble wrapping my head around some of the concepts. I just started using SQLAlchemy, But I still can't understand some concepts .

Boiled down to the essential elements, I have two tables like this (this is through Flask-SQLAlchemy): Boil down to basic elements , I have two such watches （ This is through Flask-SQLAlchemy）：

class User(db.Model):    __tablename__ = 'users'    user_id = db.Column(db.Integer, primary_key=True)class Posts(db.Model):    __tablename__ = 'posts'    post_id = db.Column(db.Integer, primary_key=True)    user_id = db.Column(db.Integer, db.ForeignKey('users.user_id'))    post_time = db.Column(db.DateTime)    user = db.relationship('User', backref='posts')

How would I go about querying for a list of users and their newest post (excluding users with no posts). How will I query the user list and its latest posts （ Users without posts are not included ）.If I was using SQL, I would do: If I use SQL, I will do this ：

SELECT [whatever]FROM posts AS p    LEFT JOIN users AS u ON u.user_id = p.user_idWHERE p.post_time = (SELECT MAX(post_time) FROM posts WHERE user_id = u.user_id)

So I know exactly the "desired" SQL to get the effect I want, but no idea how to express it "properly" in SQLAlchemy. So I know exactly “ Desired ”SQL To get the effect I want , But I don't know how to SQLAlchemy in “ Correctly ” Express it .

Edit: in case it's important, I'm on SQLAlchemy 0.6.6. edit ： In case of a one thousand , I'm using SQLAlchemy 0.6.6.

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Solution ：

Reference resources ： https://stackoom.com/en/question/Q2cS