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SISO decoder for repetition (supplementary Chapter 4)
2022-06-11 19:13:00 【Bai Xiaosheng of Ming Dynasty】
Preface :
stay LDPC,Polar Code will be involved repetion code, Here we will focus on the corresponding principle ,
Why can we add directly
One Overall process

Repetition code(3,1):
Sending process :
news bit: m Range [0,1], 1bit
After the coding : M=[m,m,m],3bit
BPSK: 1 Modulation into -1,
0 Modulation into +1
Receiver decoding process
![r=[r_1,r_2,r_3]](http://img.inotgo.com/imagesLocal/202206/11/202206111752137694_21.gif)

beliefs that
is 0
Here we mainly focus on the decoder :

Practical application factor Fixed for 1( Because it doesn't affect the final hardout This value is greater than 0, Namely 0, Less than 0 Namely 1)
Example :
For example, I received it r[3,2,4]
3: beliefs about first bit base on r1 alone
2: beliefs about second bit base on r2 alone
4: beliefs about third bit base on r3 alone

as follows r[0.1,-2.-0.5]

Two intrinsic LLR
We also call it channel LLR perhaps input LLR
Here's a detailed derivation of its principle
Let's start with a priori probability (Prior), front BEC,BSC It's all like this

,

be Using Bayesian principles :



among



be


Simplify writing

3、 ... and extrinsic LLR
Now it's given
How to find 

Here we use
For example :






When
because
Conditions are independent
therefore
Empathy
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![c_1=0,QPSK-> [+1,+1,+1]](http://img.inotgo.com/imagesLocal/202206/11/202206111752137694_25.gif)






