Integer overflow and printing

%u Description display unsigned int Type value

#include <stdio.h>
int main(void)
{
    int i = 2147483647;
    unsigned int j = 4294967295;
    printf("%d %d %d\n",i,i+1,i+2);
    printf("%u %u %u\n",j,j+1,j+2);
    return 0;
}

Output structure

2147483647 -2147483648 -2147483647
4294967295 0 1

Print short、long、long long、unsigned type

%ld For printing long Type value

%lx Used to print in hexadecimal format long Type value

%lo Used to print in octal format long Type value

%hd Indicates display in decimal short Type integer

%ho Indicates that it is displayed in octal short Type integer

%lu Means to print unsigned long Type value

%lld It means signed long long Type value

%llu To represent an unsigned long long Type value

#include <stdio.h>
int main(void)
{
    unsigned int un = 300000000;
    short end = 200;
    long big = 65537;
    long long verybig = 12345678908642;
    printf("un = %u and not %d\n",un,un);
    printf("end = %hd and %d\n",end,end);
    printf("big = %ld and not %hd\n",big,big);
    printf("verybig = %lld and not %ld\n",verybig,verybig);
    return 0;
    
}

Running results

un = 3000000000 and not -1294967296
end = 200 and 200
big = 65537 and not 1
verybig = 12345678908642 and not 194289938

This output can only have the following results in a specific system