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Talking about: is the HashSet set ordered or disordered /hashset set unique, why can we store elements with the same content
2022-07-03 08:27:00 【bai259257】
package Set;
import java.util.Collections;
import java.util.HashSet;
public class HashSetDemo01 {
public static void main(String[] args) {
//HashSet The underlying data structure of a collection is a hash table , It is a secondary data structure , The hash table is composed of an array + Linked list implementation of
//Set The characteristic of a set is that the elements are unique , Because in its system, although HashSet The order in which the set accesses data is out of order ( Of course, it may also be orderly ),
// But through in-depth analysis , We can actually see , The order of our cognition refers to the order of access ,HashSet The set is based on hash value pairs 16 Take the rest to decide which bucket to store , There is also a sequence of going deep into the bottom
//HashSet The collection has 0~15 An array of indexes of .
HashSet<dog> hashSet = new HashSet<>();
Collections.addAll(hashSet,new dog(" Darling ",1),new dog(" Recruit money ",3),new dog(" Recruit money ",3));
// We store three elements in the collection , Suppose that the two incoming fortunes are the same dog , But by printing the set, we can see that both dogs have been added
System.out.println(hashSet);

// reflection :HashSet The set should be unique to the element , However, elements with the same content can be added to the collection , Why does this happen here ?
// We need to know a method first public int hashCode(), This method is Object Class , Any object calls hashCode Methods will return the corresponding hash value , The default is generated according to the address value
// What we need to know , because int The data is -2147483648~2147483647, If there are enough elements , Object call hashCode The data obtained by the method will certainly be repeated , This is called hash collision .
//HashSet The underlying data structure of a collection is an array + Linked list , When creating this collection , It initializes a with a length of 16 Array of , Each array stores linked list nodes . Its storage characteristics are determined by the hash value , It will make every element call hashCode Method , Make hash value pairs 16 Remainder , The remainder is stored in the bucket , Judge whether there are elements in the bucket , If there is no element , It is stored as the head node of the current bucket
// If there are elements in the bucket ,(1) First judge and compare the hash value of this element with the hash value of the bucket , Even if the hash values of two elements are the same , The system will not think that elements are repeated , Because hash collision may occur , Although the possibility is relatively small , But it can also happen
//(2) Next we will use equals Method to compare the address value of the element to be stored with the address value of the element in the bucket , Because the objects are new Coming out , The address in the heap space is unique , So whether the content is the same or not , Will be stored in the collection
// Here we can make it clear ,hashSet Collections store data elements , Is determined by the hash value , The underlying hash value is determined by the address value . Originally in hashSet Determine whether the elements are repeated in the set In the final analysis, it is to judge the address value of two elements !
// And we don't want to add elements through address values at all , Instead, I want to judge the content .
// Solutions :
// Override in the class of the object element equals as well as hashCode Method .
// The rewritten equals The bottom layer of the method is to compare the content ,hashCode Methods are also generated based on content .
// After rewriting , Set stored data , It still makes every element call hashCode Method to get the hash value , We need to know that the current hash value is generated through content , So if there are elements in the bucket to be stored , Judge whether the hash value of the element in the bucket is the same , If it's different, deposit it directly ,
// If the same, it will be considered that hash collision occurs ,(2) Use equals Method to judge the content between elements , If different, it is stored in the set , If true It is clear that this is a repeating element !

}
}
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