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Mathematical knowledge arrangement: extremum & maximum, stagnation point, Lagrange multiplier
2022-06-13 01:02:00 【UQI-LIUWJ】
1 extremum
1.1 Stagnation point
- If the function z=f(x,y) At point
There's an extreme value at , And partial derivative exists , that z=f(x,y) stay
The partial derivative at must be 0, namely 
- To satisfy
The point of
For the function z=f(x,y) Stop at , Also known as the equilibrium point - z=f(x,y) Its extreme point must be the point where its stagnation point or partial derivative does not exist ; however The stagnation point is not necessarily the extreme point
- such as z=f(x,y)=xy, stay (0,0) Obviously there is
, That is to say (0,0) yes f(x,y) A stopping point of , however (0,0) It is not the extreme point of the function ( Just a saddle point )
1.1.1 The sufficient condition that the stagnation point is the extreme point
- such as z=f(x,y)=xy, stay (0,0) Obviously there is
set up z=f(x,y) A point in the definition field
Where there is a second-order continuous partial derivative , And 
We remember
,
, be
- When Δ>0,A>0 when ,f(x,y) stay spot
There is a minimum at When Δ>0,A<0 when ,f(x,y) stay spot
There is a maximum at When Δ<0 when , f(x,y) stay spot
There is no extreme value at
2 The most value
Find the function in the region D The general way to get the best value on is , First, find out the function in the region D Internal extremum , Is that the function is in D Compare the maximum value on the boundary of .

For some problems , We can know that the maximum value of a function exists , And in the area D Internal . If the function is in the region D The inner partial differential exists , And there is only one stopping point
, Then this stagnation point is the most valuable
3 Conditional extremum
Seeking function z=f(x,y) Meet the conditions
Conditional extremum of
3.1 The conditional extremum is transformed into ordinary extremum
From the conditional equation
The solution is given in the paper y=g(x), Plug in z=f(x,y) in
3.2 Lagrange multiplier
(1) Write auxiliary functions 
(2)x,y,λ The system of equations satisfied

(3) From the above equations (x,y) Is the point where the conditional extremum may be taken
seek m Meta function +n The two constraints are the same
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, That is to say (0,0) yes f(x,y) A stopping point of , however (0,0) It is not the extreme point of the function ( Just a saddle point )