Phased learning about the entry-level application of SQL Server statements - necessary for job hunting (I)

First stage exercise

*************** This chapter is suitable for non basic learners or those who have a certain foundation but do not have a solid grasp of knowledge ******************************
The following exercises are performed according to the tables initialized into the database , Please be sure to execute the following table creation statement first .

create table s1_student( sno varchar2(10) primary key, sname varchar2(30), sbirthday varchar2(30), ssex varchar2(10),sclass varchar2(10) ); 
create table s1_teacher(  tno varchar2(10) primary key, tname varchar2(30),tsex varchar2(10),tbirthday varchar2(30),prof varchar2(30),depart varchar2(30) );  
create table s1_course( cno varchar2(10), cname varchar2(30),  tno varchar2(10) ); 
create table s1_score( sno varchar2(10), cno varchar2(10),  degree number );
create table s1_grade( low number, upp number,  rank varchar2(2) );

*/ Initialize student table s1_student/

insert into s1_student values ('108', ' Zeng Hua ', '1997/9/1', ' male ', '95033');
insert into s1_student values ('105', ' Kuang Ming ', '1995/10/2', ' male ', '95031');
insert into s1_student values ('107', ' Wang Li ', '1996/1/23', ' Woman ', '95033');
insert into s1_student values ('101', ' Li Jun ', '1996/2/20', ' male ', '95033');
insert into s1_student values ('109', ' Wang Fang ', '1995/2/10', ' Woman ', '95031');
insert into s1_student values ('103', ' Lu Jun ', '1994/6/3', ' male ', '95031');
commit; 

/ Initialize the teacher table s1_teacher/

insert into s1_teacher values ('804', ' Li Cheng ',' male ','1979-12-2',' associate professor ',' Department of Computer Science '); 
insert into s1_teacher values ('856', ' Zhang Xu ',' male ','1985-3-12',' lecturer ',' Department of electronic engineering '); 
insert into s1_teacher values ('825', ' Wang Ping ',' Woman ','1989-5-2',' Assistant ',' Department of Computer Science '); 
insert into s1_teacher values ('831', ' Liu Bing ',' Woman ','1988-8-2',' Assistant ',' Department of electronic engineering '); 
commit; 
/******* first 

Initial Curriculum s1_course********/

insert into s1_course values ('3-105', ' Introduction to computer ', '825');
insert into s1_course values ('3-245', ' operating system ', '804');
insert into s1_course values ('6-166', ' Data circuits ', '856');
insert into s1_course values ('9-888', ' Advanced mathematics ', '800');
commit; 

/ Initialize the grade sheet s1_score*/

insert into s1_score values ('103', '3-245', 86);
insert into s1_score values ('105', '3-245', 75);
insert into s1_score values ('109', '3-245', 68);
insert into s1_score values ('103', '3-105', 92);
insert into s1_score values ('105', '3-105', 88);
insert into s1_score values ('109', '3-105', 76);
insert into s1_score values ('101', '3-105', 64);
insert into s1_score values ('107', '3-105', 91);
insert into s1_score values ('108', '3-105', 78);
insert into s1_score values ('101', '6-166', 85);
insert into s1_score values ('107', '6-106', 79);
insert into s1_score values ('108', '6-166', 81);
commit;  

/ Initialize the grade classification table s1_grade*/

insert into s1_grade values ('90', '100', 'A');
insert into s1_grade values ('80', '89', 'B');
insert into s1_grade values ('70', '79', 'C');
insert into s1_grade values ('60', '69', 'D');
insert into s1_grade values ('0', '59', 'E');
commit;

1. Inquire about s1_student All the records in the table Sname、Ssex and Class Column .

select sname,ssex,sclass from s1_student;

2. Query all the units of the teacher is not repeated Depart Column .

select distinct depart from s1_teacher;

3. Inquire about s1_student All the records of the table .

select * from s1_student;

4. Inquire about s1_score The score in the table is 60 To 80 All records between .

select * from s1_score where degree between 60 and 80;

5. Inquire about s1_score The score in the table is 85,86 or 88 The record of .

select * from s1_score where degree in (85,86,88);

6. Inquire about s1_student In the table “95031” Class or gender is “ Woman ” Of the students .

select * from s1_student where sclass='95031' or ssex=' Woman ';

7. With Class Descending query s1_student All the records of the table .

select * from s1_student order by sclass desc;

8. With Cno Ascending 、Degree Descending query s1_score All the records of the table .

select * from s1_score order by cno,degree desc;

9. Inquire about “95031” The number of students in the class .

select count(sno) from s1_student where sclass='95031';

10. Inquire about s1_score The student number and course number with the highest score in the table .

select sno,cno from s1_score where degree =(select max(degree) from s1_score);

11. Inquire about ‘3-105’ The average score of course No .

select avg(degree) from s1_score where cno='3-105';

12. Inquire about s1_score There is at least 5 Three students took the course and took 3 The average score of the first course .

select cno,avg(degree) from s1_score where cno like '3%' group by cno having count(sno)>5;

13. The minimum query score is greater than 70, The highest score is less than 90 Of Sno Column .

select sno from s1_score group by sno having min(degree)>70 and max(degree)<90;

14. Look up all the students Sname、Cno and Degree Column .

select sname,cno ,degree from s1_student st,s1_score sc where st.sno=sc.sno(+);

15. Look up all the students Sno、Cname and Degree Column .

select sno,cname,degree from s1_score sc,s1_course co where sc.cno(+)=co.cno;

16. Look up all the students Sname、Cname and Degree Column .

select sname,cname,degree from s1_student st,s1_score sc,s1_course co where  st.sno=sc.sno(+) and sc.cno=co.cno(+);

17. Inquire about “95033” The average score of the course chosen by the class .

select avg(degree) from s1_score sc,s1_student st where st.sno=sc.sno and sclass='95033';

18. Now I want to check all the students Sno、Cno and rank Column .

select sno,cno,degree,(select rank from s1_grade where low<=degree and upp>=degree)as rank  from s1_score;

19. Check options “3-105” The grade of the course is higher than “109” The records of all the students in the grade of No .

(1)select * from s1_score where cno='3-105' and degree >(select degree from s1_score where cno='3-105' and sno='109');
(2)select x.CNO ,x.SNO ,x.DEGREE  from s1_score  x,s1_score  y
 where x.CNO ='3-105' and x.DEGREE >y.DEGREE and y.SNO ='109'and y.CNO='3-105';

20. Inquire about s1_score The record that the score of students who choose to study more than one course is not the highest score .

select * from s1_score j  where j.SNO  in (
       select SNO  from s1_score group by SNO having count(*)>=2) and 
              j.DEGREE <(select max(DEGREE)from s1_score b where b.CNO = j.CNO );

21. The inquiry result is higher than the student number “109”、 The course number is “3-105” All records of the results of .

select * from s1_score where degree>(select degree from s1_score where sno='109'and cno='3-105') and cno='3-105';

22. The inquiry and student ID are 108 Of all students born in the same year Sno、Sname and Sbirthday Column .

select sno,sname,sbirthday from s1_student st1 where substr(sbirthday,1,4)in (select substr(sbirthday,1,4) from s1_student where sno='101');

23. Inquire about “ Zhang Xu “ The results of the students who teach .

select sc.* from s1_score sc,s1_teacher th,s1_course co where sc.cno=co.cno and co.tno=th.tno and th.tname=' Zhang Xu ';

24. The number of students taking a course is more than 5 The teacher's name .

(1)select tname from s1_teacher th,s1_course co where th.tno=co.tno and co.cno in       (select cno from s1_score group by cno having count(sno)>5);
(2)select TNAME  from s1_teacher where TNO in(
     select x.TNO from s1_course x inner join s1_score y on x.CNO =y.CNO 
            group by x.TNO having count(x.TNO )>5);

25. Inquire about 95033 Class and 95031 A record of all the students in the class .

select * from s1_student where sclass in('95033','95031');

26. There are 85 A course with a score of above Cno.

select cno from s1_score group by cno having max(degree)>=85;

27. Query out “ Department of Computer Science “ The teacher's score sheet for the course .

select sc.* from s1_score sc,s1_teacher th,s1_course co where sc.cno=co.cno and co.tno=th.tno and th.depart=' Department of Computer Science ';

28. Inquire about “ Department of Computer Science ” And “ Department of electronic engineering “ Teachers with different titles Tname and Prof.

select TNAME,PROF from s1_teacher  where DEPART =' Department of Computer Science ' and PROF not in(
       select PROF from s1_teacher where DEPART =' Department of electronic engineering ');

29. The number of the elective course is “3-105“ The course and the score shall be at least higher than the elective number “3-245” Of my classmates Cno、Sno and Degree, And press Degree Order from high to low .

(1)select sno,cno,degree from s1_score where cno='3-105' and degree >(
         select min(degree) from s1_score where cno='3-245')order by degree desc;
(2)select * from s1_score where CNO ='3-105' and DEGREE >any (
          select DEGREE  from s1_score where CNO ='3-245')order by DEGREE desc;

30. The number of the elective course is “3-105” And the score is higher than the elective number “3-245” Of the class Cno、Sno and Degree.

(1)select sno,cno,degree from s1_score where cno='3-105' and degree >(
         select max(degree) from s1_score where cno='3-245')order by degree desc;
(2)select * from s1_score where CNO ='3-105' and DEGREE >all(
         select DEGREE  from s1_score where CNO ='3-245');

31. Check all the teachers and students name、sex and birthday.

select sname as name,ssex as sex from s1_student
union all
select tname as name,tsex as sex from s1_teacher;

32. Query all “ Woman ” Teachers and “ Woman ” Classmate name、sex and birthday.

select sname as name,ssex as sex,sbirthday as birthday from s1_student where ssex=' Woman '
union all
select tname as name,tsex as sex,tbirthday as birthday from s1_teacher where tsex=' Woman ';

33. Look up the grade table of the students whose grades are lower than the average of the course .

(1)select sc1.* from s1_score sc1,(select cno,avg(degree)as degree from s1_score group   by cno) sc2   where sc1.cno=sc2.cno and sc1.degree<sc2.degree;
(2)select * from s1_score a where DEGREE <(
        select avg(DEGREE) from s1_score b where a.CNO=b.CNO);

34. Look up all the teachers Tname and Depart.

(1)select tname,depart from s1_teacher th,s1_course co where th.tno=co.tno;
(2)select TNAME,DEPART from s1_teacher where exists
     (select * from s1_course  where s1_course.TNO = s1_teacher.TNO );

35. Look up all the teachers who didn't give lectures Tname and Depart.

(1)select tname,depart from s1_teacher th where th.tno not in (
          select tno from s1_course);
(2)select tname,depart from s1_teacher th where not exists (
          select tno from s1_course co where th.tno=co.tno); 

36. At least there are 2 Class number of three boys .

select sclass from s1_student where ssex=' male ' group by sclass having count(sno)>=2;	

37. Inquire about s1_student There is no surname in the table “ king ” Of the students .

select * from s1_student where sname not like ' king %';

38. Inquire about s1_student The name and age of each student in the table .

select sname,to_char(sysdate,'yyyy')-substr(sbirthday,1,4) as tage from s1_student;

39. Inquire about s1_student The largest and smallest of the tables Sbirthday Date value .

select max(sbirthday),min(sbirthday) from s1_student;

40. Search by shift number and age from big to small s1_student All the records in the table .

select * from s1_student order by sclass desc,sbirthday asc;

41. Inquire about “ male ” Teachers and their courses .

select th.tno,th.tname,th.tsex,co.cno from s1_teacher th,s1_course co where th.tno=co.tno and th.tsex=' male ';

42. Look up the students with the highest scores Sno、Cno and Degree Column .

select * from s1_score where degree =(select max(degree) from s1_score);

43. Query and “ Li Jun ” All other classmates of the same sex Sname.

select sname from s1_student where ssex =(select ssex from s1_student where sname=' Li Jun ') and sname<>' Li Jun ';

44. Query and “ Li Jun ” Same sex classmates Sname.

(1)select sname from s1_student st1 where exists 
    (select *  from s1_student st2 where st2.sname=' Li Jun ' and st1.sclass=st2.sclass and st1.ssex=st2.ssex);
(2)select SNAME from s1_student where SSEX =(select SSEX from s1_student where SNAME =' Li Jun ') and SCLASS =(select SCLASS from s1_student where SNAME =' Li Jun ');

45. Check all electives “ Introduction to computer ” Curriculum “ male ” Student's score sheet

(1)select sc.* from s1_score sc,s1_course co,s1_student st 
         where sc.sno=st.sno and sc.cno=co.cno and co.cname=' Introduction to computer ' and st.ssex=' male ';
(2)select * from s1_score  where SNO  in(select SNO  from s1_STUDENT  where SSEX =' male ') 
         and CNO =(select CNO  from s1_COURSE  where CNAME =' Introduction to computer ');