C191: password compilation

Problem description ：

There is a line of telegram , It has been translated into a password according to the following rules ：
A>>Z a>>z
B>>Y b>>y
C>>X c>>x
. .
. .
. .
wait . That is to say 1 The first letter becomes the 26 Letters , The first i The first letter becomes the （26-i+1） Letters , Non alphabetic characters remain unchanged , Require the programmer to translate the password into the original .

Enter description ：

Enter a string of characters （ contain 7 Elements ）, The password .

The output shows that ：

Output its corresponding characters （ contain 7 Elements ）, Express the original text .

sample input ：

ABCDEFG

sample output ：

ZYXWVUT

#include<stdio.h>
int main()
{
    
	char m[7];
	int i;
	scanf("%s",m);
	for(i=0;i<7;i++)
	{
    
		if(m[i]>='A'&&m[i]<='Z')
		{
    
			m[i]='A'+26-(m[i]-'A'+1);
		}
		else if(m[i]>='a'&&m[i]<='z')
		{
    
			m[i]='a'+26-(m[i]-'a'+1);
		}
	}
	for(i=0;i<7;i++) printf("%c",m[i]);
	return 0;
}