If there is a declaration "int x=5, y=1;", Then the expression x < y? The result of x++: y++ is:

If there is a statement ”int x=5,y=1;”, Expression x<y?x++:y++ The result is ：

  1 #include<stdio.h>
  2 
  3 int main(int argc,const char* argv[])
  4 {
    
  5     int x=5,y=1;
  6     printf("%d",(x<y?x++:y++));
  7     return 0;
  8 }

expression ：x<y?x++:y++

because x++; y++;
++ To the right of the variable , First operation and then self addition 1,
So it's equivalent to ：x<y?x:y