当前位置:网站首页>Macro task and micro task understanding
Macro task and micro task understanding
2022-06-27 22:17:00 【You must try, but don't worry】
1. What is a macro task Micro task
js It's a single thread language Simply speaking There is only one channel When there are many tasks There will be congestion This situation arises ‘ Multithreading ’ But this kind of ‘ Multithreading ’ It is imitated by single thread That's fake Then there is Sync 、 Asynchronous task .
2.JS Why distinguish Macro task 、 Micro task
1 js It's single threaded But sub synchronous asynchronous
2 Macro task 、 All micro tasks are Asynchronous task They all belong to a queue
3. Macro task 、 Micro task What are they?
Macro task script、setTimeout、setInterval、postMessage、MessageChannel、setImmediate
Micro task Promise.then、Object.observe、MutationObserver、process.nextTick
4. Macro task 、 Micro task How to execute
Execute synchronization code first
encounter Asynchronous macro task Will Asynchronous macro task Put in Macro task queue
encounter Asynchronous micro task Will Asynchronous micro task Put in In the micro task queue
When all synchronization code is executed
then Asynchronous micro task Call in from the queue Main thread execution
When the micro task is completed
then Asynchronous macro task Call in from the queue Main thread execution
Cycle all the time until All tasks are completed
5. Case study
setTimeout(function(){
console.log(1)
})
new Promise(function(resolve){
console.log(2)
resolve()
}).then(function(){
console.log(3)
}).then(function(){
console.log(4)
})
console.log(5)
// 2 5 3 4 1
- encounter setTimeout Asynchronous macro task Put in the macro task queue
- encounter new Promise new Promise The code executed when instantiating is synchronous So the output 2
- Promise then Asynchronous micro task Put it in the queue of microtasks
- Encounter synchronization task Output 5 The synchronization task in the main thread has finished executing
- take Asynchronous micro task Call in from the queue Main thread execution Output 3 4 The micro task queue is empty
- take Asynchronous macro task Call in from the queue Main thread execution Output 1 Macro task queue is empty
setTimeout(() => {
new Promise(resolve => {
resolve()
}).then(() => {
console.log('test')
})
console.log(4)
})
new Promise(resolve => {
resolve()
console.log(1)
}).then( () => {
console.log(3)
Promise.resolve().then(() => {
console.log('before timeout')
}).then(() => {
Promise.resolve().then(() => {
console.log('also before timeout')
})
})
})
console.log(2)
// 1, 2, 3, before timeout, also before timeout, 4, test
- encounter setTimeout Asynchronous macro task Put in the macro task queue
- encounter new Promse new Promse When instantiating The code executed is synchronized So the output 1
- and Promise.then Asynchronous micro task Put it in the queue of microtasks
- Encounter synchronization task Output 2 The synchronization task in the main thread has finished executing
- take Asynchronous micro task Call in from the queue Main thread execution Output 3
In this micro task There are micro tasks Promise.resolve().then( Micro task A).then( Micro task B) Put them in the micro task queue in turn- From the micro task queue Take out Micro task A Put in In the main thread Output before timeout
- From the micro task queue Take out Micro task B Put in In the main thread Micro task B And then there is Micro task C Put it in the queue of microtasks
- From the micro task queue Take out Micro task C Put in In the main thread Output also before timeout The micro task queue is empty
- From the macro task queue Take out Macro task Put in In the main thread This task There is a micro task D Put it in the queue of microtasks Next, output 4 Macro task queue is empty
- From the micro task queue Take out Micro task D Put in In the main thread Output test The micro task queue is empty
console.log(1)
setTimeout(function() {
console.log(2)
}, 0)
const p = new Promise((resolve, reject) => {
resolve(4)
})
p.then(data => {
console.log(data)
})
console.log(3)
// 1, 3, 4, 2
- Encounter synchronization task Output 1
- encounter setTimeout Asynchronous macro task Put in the macro task queue
- encounter Promise new Promise The code executed during instantiation is synchronized But because of new Promse No output events So go ahead and do encounter .then
- perform .then Asynchronous micro task Put in In the micro task queue
- Encounter synchronization task Output 3 The synchronization task in the main thread has finished executing
- from In the micro task queue Take out Micro task Put in In the main thread Output 4 The micro task in the main thread has finished executing
- from Macro task queue Take out Macro task Put in In the main thread Output 2 The macro task in the main thread has finished executing
console.log(1)
setTimeout(function() {
console.log(2)
new Promise(function(resolve) {
console.log(3)
resolve()
}).then(function() {
console.log(4)
})
})
new Promise(function(resolve) {
console.log(5)
resolve()
}).then(function() {
console.log(6)
})
setTimeout(function() {
console.log(7)
new Promise(function(resolve) {
console.log(8)
resolve()
}).then(function() {
console.log(9)
})
})
console.log(10)
// 1, 5, 10, 6, 2, 3, 4, 7, 8, 9
- Encounter synchronization task Output 1
- encounter setTimeout Asynchronous macro task Put in the macro task queue
- encounter Promise new Promise The code executed during instantiation is synchronized So the output 5 So go ahead and do encounter .then
- perform .then Asynchronous micro task Put in Micro task queue in
- encounter setTimeout Asynchronous macro task Put in Macro task queue
- Encounter synchronization task Output 10 The synchronization task in the main thread has finished executing
- from In the micro task queue Take out Micro task Put in In the main thread Output 6 The micro task in the main thread has finished executing
- from Macro task queue Take out Macro task Put in In the main thread Execute the first Output 2 3 4
- Carry out the second setTimeout Output 7 8 9 The macro task in the main thread has finished executing
new Promise((resolve, reject) => {
resolve(1)
new Promise((resolve, reject) => {
resolve(2)
}).then(data => {
console.log(data)
})
}).then(data => {
console.log(data)
})
console.log(3)
// 3, 2, 1
- encounter Promise new Promise The code executed during instantiation is synchronized But because of No output events
So go on encounter new Promse No output events And then go on encounter .then Asynchronous micro task Put it in the queue of microtasks- We'll go on with the .then Asynchronous micro task Put it in the queue of microtasks
- Encounter synchronization task Output 3 The synchronization task in the main thread has finished executing
- From the micro task queue Take out Micro task Put in The main thread in Output 2 3 The micro task in the main thread has finished executing Task queue is empty
summary
First synchronous then asynchronous
asynchronous contain Macro task Micro task
asynchronous encounter Micro task Do the micro task first After the execution If there is no micro task Just go to the next macro task
边栏推荐
- Go from introduction to actual combat - task cancellation (note)
- Gbase 8A OLAP analysis function cume_ Example of dist
- Selenium上传文件有多少种方式?不信你有我全!
- Yarn performance tuning of CDH cluster
- 使用sqlite3语句后出现省略号 ... 的解决方法
- 渗透学习-sql注入过程中遇到的问题-针对sort=left(version(),1)的解释-对order by后接字符串的理解
- .NET学习笔记(五)----Lambda、Linq、匿名类(var)、扩展方法
- Ellipsis after SQLite3 statement Solutions for
- matlab查找某一行或者某一列在矩阵中的位置
- QT base64 encryption and decryption
猜你喜欢
![[LeetCode]动态规划解分割数组II[Arctic Fox]](/img/a1/4644206db3e14c81f9f64e4da046bf.png)
[LeetCode]动态规划解分割数组II[Arctic Fox]

C语言程序设计详细版 (学习笔记1) 看完不懂,我也没办法。

管理系统-ITclub(下)

This set of steps for performance testing using JMeter includes two salary increases and one promotion
![[LeetCode]动态规划解拆分整数I[Silver Fox]](/img/18/8dc8159037ec1262444db8899cde0c.png)
[LeetCode]动态规划解拆分整数I[Silver Fox]

Figure countdownlatch and cyclicbarrier based on AQS queue

不外泄的测试用例设计秘籍--模块测试
扁平数组和JSON树的转换

6G显卡显存不足出现CUDA Error:out of memory解决办法

关于davwa的SQL注入时报错:Illegal mix of collations for operation ‘UNION‘原因剖析与验证
随机推荐
Système de gestion - itclub (II)
宏任务、微任务理解
Acwing week 57 longest continuous subsequence - (binary or tree array)
[LeetCode]513. 找树左下角的值
Use Fiddler to simulate weak network test (2g/3g)
GBase 8a的create database 会被查询耗时很长怀疑卡住的现象分析
regular expression
Hash table - sum of arrays
[sword offer ii] sword finger offer II 029 Sorted circular linked list
深度学习又有新坑了!悉尼大学提出全新跨模态任务,用文本指导图像进行抠图
Go from introduction to practice -- definition and implementation of behavior (notes)
[LeetCode]515. Find the maximum value in each tree row
[LeetCode]100. Same tree
[LeetCode]动态规划解拆分整数I[Silver Fox]
二维数组中修改代价最小问题【转换题意+最短路径】(Dijkstra+01BFS)
[LeetCode]动态规划解分割数组I[Red Fox]
Read write separation master-slave replication of MySQL
qt 大文件生成md5校验码
QT base64 encryption and decryption
How many ways does selenium upload files? I don't believe you have me all!