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On the escape of inequality value
2022-06-26 18:45:00 【51CTO】
Recently I met a need , Front end filling inequality , The back end needs to be stored , It is necessary to translate the inequality into the form of interval , Let's share some general solutions , For reference only .
One 、 Agree with the front end on the data format to be transmitted
The front page display is like this
The parameter transfer format agreed with the front end is
utilize @ Symbols separate symbols from version numbers , This symbol can also be used for subsequent stock in , There are multiple rules that can be passed to a string array , You can also pass comma separated strings
Two 、 Verify before warehousing
// Check the maximum and minimum version numbers of multiple rules
versionRangeList :
=
strings
.
Split(
body
.
VersionRange,
",")
switch
len(
versionRangeList) {
case
1:
version :
=
strings
.
Split(
versionRangeList[
0],
"@")
switch
version[
0] {
case
GT,
GE,
LT,
LE,
EQ,
NE:
// Normal rule
default:
return
tracerr
.
NewError(
" The rules are illegal , Parameter transfer exception ："
+
versionRangeList[
0])
}
case
2:
version1 :
=
strings
.
Split(
versionRangeList[
0],
"@")
version2 :
=
strings
.
Split(
versionRangeList[
1],
"@")
switch
version1[
0] {
case
GT,
GE:
if
version1[
1]
>=
version2[
1]
|| (
version2[
0]
!=
LT
&&
version2[
0]
!=
LE) {
return
tracerr
.
NewError(
" The rules are illegal , The minimum version number is not less than the maximum version number ")
}
case
LT,
LE:
if
version1[
1]
<=
version2[
1]
|| (
version2[
0]
!=
GT
&&
version2[
0]
!=
GE) {
return
tracerr
.
NewError(
" The rules are illegal , The minimum version number is not less than the maximum version number ")
}
default:
return
tracerr
.
NewError(
" The rules are illegal , Multiple rules can only be selected ：gt,ge,lt,le")
}
default:
return
tracerr
.
NewError(
" The rules are illegal , The number of rules is abnormal , The number of rules is ："
+
strconv
.
Itoa(
len(
versionRangeList)))
}
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3、 ... and 、 Escape to interval
Because it is necessary to convert inequality into interval form and transmit it to other modules , So I chose to create one map, Establish the corresponding relationship between inequality and interval scheme
// Inequality constant
const (
GT
=
"gt"
// Greater than
GE
=
"ge"
// Greater than or equal to
LT
=
"lt"
// Less than
LE
=
"le"
// Less than or equal to
EQ
=
"eq"
// be equal to
NE
=
"ne"
// It's not equal to
)
func
RuleReversal(
versionRange []
string) (
reversalResult
string) {
// Reverse the rules Map
ruleReversalMap :
=
map[
string]
string{
GT:
"(,Ver]",
GE:
"(,Ver)",
LT:
"[Ver,)",
LE:
"(Ver,)",
EQ:
"(,Ver),(Ver,)",
NE:
"[Ver]",
}
switch
len(
versionRange) {
case
1:
version :
=
strings
.
Split(
versionRange[
0],
"@")
reversalResult
=
strings
.
ReplaceAll(
ruleReversalMap[
version[
0]],
"Ver",
version[
1])
case
2:
version1 :
=
strings
.
Split(
versionRange[
0],
"@")
version2 :
=
strings
.
Split(
versionRange[
1],
"@")
switch
version1[
0] {
case
GT,
GE:
reversalResult
=
strings
.
ReplaceAll(
ruleReversalMap[
version1[
0]],
"Ver",
version1[
1])
+
","
+
strings
.
ReplaceAll(
ruleReversalMap[
version2[
0]],
"Ver",
version2[
1])
case
LT,
LE:
reversalResult
=
strings
.
ReplaceAll(
ruleReversalMap[
version1[
0]],
"Ver",
version1[
1])
+
","
+
strings
.
ReplaceAll(
ruleReversalMap[
version2[
0]],
"Ver",
version2[
1])
default:
tracerr
.
Print(
errors
.
New(
" The rules are illegal , Version inequality exception ："
+
version1[
0]))
return
""
}
default:
tracerr
.
Print(
errors
.
New(
" The rules are illegal , The number of rules is abnormal , The number of rules is ："
+
strconv
.
Itoa(
len(
versionRange))))
return
""
}
return
reversalResult
}
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utilize @ Symbols separate symbols from version numbers , Remove the separated inequality symbols map Get the corresponding interval format in , Then, the separated version number is matched to the... In the obtained interval format Ver Replace it .
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