1016 part a+b (15 points)

Positive integer A Of “DA​（ by 1 An integer ） part ” Defined by A All in DA​ A new integer composed of PA​. for example ： Given A=3862767,DA​=6, be A Of “6 part ”PA​ yes 66, because A There is 2 individual 6.

Now given A、DA​、B、DB​, Please write a program to calculate PA​+PB​.

Input format ：

The input is given in turn on a line A、DA​、B、DB​, Space between , among 0<A,B<109.

Output format ：

Output in one line PA​+PB​ Value .

sample input 1：

3862767 6 13530293 3

sample output 1：

399

sample input 2：

3862767 1 13530293 8

sample output 2：

0

Small simulation No difficulty

#include <iostream>
#include <algorithm>
#include <cstring>
#include <vector>
using namespace std;
vector<int> a, b;

int main()
{
    long long  m, x, n, y;
    cin >> x >> m >> y >> n;
    while(x)
    {
        if(x % 10 == m) a.push_back(m);
        x /= 10;
    }
    while(y)
    {
        if(y % 10 == n) b.push_back(n);
        y /= 10;
    }
    int sum1 = 0, sum2 = 0;
    for (int i = 0; i < a.size(); i ++ )
    {
        sum1 *= 10;
        sum1 += a[i];
    }
    for (int i = 0; i < b.size(); i ++ )
    {
        sum2 *= 10;
        sum2 += b[i];
    }
    cout << sum1 + sum2 << endl;
    return 0;
}