Each account corresponds to all passwords, and then each password corresponds to all accounts. How to write the brute force cracking code

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One 、 Preface

A few days ago Python The strongest King exchange group 【 lonely 】 Asked a question Python Issues dealt with , As shown in the figure below .

Now there are two account and password explosion files , Want to try every account number corresponding to all passwords first, and then try every password corresponding to all accounts .

In fact, each account corresponds to the password once , There is no need for each password to correspond to the account number again .

Two 、 Implementation process

In fact, I was cracking this problem before my neighbor's little sister wifi When it comes to passwords , I've thought about it , But there was no action , Just think about it, and then there's no .

here 【D I Y】 Gave an answer , Regardless of efficiency , Use double loop to force write .

later 【 Mr. Yu Liang 】 A sample code is given , As shown below ：

pw = [1,2,3,4,5]
user = ['a','b','c']
for i in user:
    for j in pw:
        print(i, j)

After running , The result is as follows ：

Even if the number of lines in the password file of two accounts （ password 7 Thousands of lines , account number 8 Thousands of lines ） It doesn't matter if it doesn't . Because of all the circumstances , Can be traversed .l

If there is a problem , Feel free to contact me to solve , Welcome to my Python Learning exchange group .

3、 ... and 、 summary

Hello everyone , I'm Pippi . This article mainly makes an inventory of Python The problem of data processing , In this paper, the specific analysis and code implementation are given , Help the fans solve the problem smoothly .

Finally, thank the fans 【 lonely 】 put questions to , thank 【 Mr. Yu Liang 】、【DIY】 Given the idea and code analysis , thank 【dcpeng】 And others participate in learning and communication .

friends , Practice it quickly ！ If in the process of learning , Any problems encountered , Welcome to add my friend , I'll pull you in Python The learning exchange group discusses learning together .

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