Example of MATLAB dichotomy (example of finding zero point by dichotomy)

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matlab Dichotomy topic

equation y=sinx In the interval [-1,2] Has a unique real root , If you use dichotomy to find the root , And the error shall not exceed 10^6, How many times do you need two points ？

tol=0.000001;% tolerance a=-1;% Enter two endpoint values b=2; ya=feval(@f,a);% hold a Assign to ya yb=feval(@f,b); max=round((log(b-a)-log(tol))/log(2))% Maximum number of iterations if yayb>0 fprintf(“ Dichotomy does not apply ”) else for k=1:max% loop c=(a+b)/2 yc=feval(@f,c); if yc==0 b=c; a=c; elseif ycyb>0 b=c; else a=c; end err(k)=b-a; if err(k)<tol break end end fprintf(“ The result is ：%f”,(a+b)/2);% The position of this step is different , Will make the number of cycles different end function [y]=f(x) y=sin(x); end

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