Battle plague Cup -- my account book

My account book
The current situation of epidemic prevention and control is grim , In order to reduce the gathering of students caused by eating , It is stipulated that a representative should be sent out to buy food every time in a dormitory , Small W In the bedroom 6 people （ Number 1-6） Decided to send one person to buy it at a time 6 The same set meal . But it's more troublesome to transfer money immediately after each purchase , So they agreed that every time they went to buy food, they would pay in advance , After the epidemic is over, the unified settlement will be made .

Now I'll give you the time during the closed management of your dormitory n The serial number of each meal buyer and the unit price of each meal , Ask everyone about the income and expenditure of meal money after the end of the epidemic ？

Input format :
First line a positive integer n, Express n Meal
below n That's ok , The first i Line two positive integers x,y It means the first one i The meal consists of x Go buy food , Unit price per meal y element .

Output format :
Six integers in a row represent the money everyone owes others or others owe him .
If he owes someone money , Output negative .
If someone owes him money , Output positive numbers .

Note that there should be no extra spaces at the end of the line ！

sample input :

3
1 5
2 10
3 5

sample output :

10 40 10 -20 -20 -20

#include<stdio.h>
int main() {
    
	int a[7] = {
    0};// Array a It's used to find out how the dormitory members buy meals , Subscript indicates member 
	int b[7] = {
    0};// Array b It means that each member of the dormitory owes money 
	int n, i, t,x;
	int sum = 0;
	scanf("%d",&n);
	for (i = 1; i <= n; i++) {
    
		scanf("%d %d",&t,&x);
		a[t] += x;// Express t Members buy meals , And the unit price of each meal is x element 
		sum += x;// Calculate how much each person spent 
	}
	for (i = 1; i <= 6; i++) {
    
		b[i] = a[i]*6 - sum;
	}
	for (i = 1; i <= 6; i++) {
    
		if (i != 6) printf("%d ",b[i]);
		else printf("%d",b[i]);
	}
}