1065 A+B and C (64bit)

Given three integers A, B and C in (−263,263), you are supposed to tell whether A+B>C.

Input Specification:

The first line of the input gives the positive number of test cases, T (≤10). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.

Output Specification:

For each test case, output in one line Case #X: true if A+B>C, or Case #X: false otherwise, where X is the case number (starting from 1). Each line should ends with '\n'.

Sample Input:

3
1 2 3
2 3 4
9223372036854775807 -9223372036854775808 0

Sample Output:

Case #1: false
Case #2: true
Case #3: false

#include <iostream>
#include <string>
#include <cmath>
#include <algorithm>
#include <stdlib.h>
using namespace std;
long long int a, b, c, t, n, sum;

int main() {
	cin >> t;
	while (t--) {
		scanf("%lld %lld %lld",&a, &b, &c);
		n++;
		sum = a + b;
		cout << "Case #" << n << ": ";
		if (a > 0 && b > 0 && sum < 0) {
			cout << "true" << endl;
		} else if (a < 0 && b < 0 && sum >= 0) {
			cout << "false" << endl;
		} else {
			if (sum > c) {
				cout << "true" << endl;
			} else {
				cout << "false" << endl;
			}
		}
	}
	return 0;
}

 参考博客：1065 A+B and C (64bit) (20分)_mob60475705f1df的技术博客_51CTO博客