C language programming -- input a string (including letters, numbers, punctuation marks, and space characters) from the keyboard, calculate the actual number of characters and print out, that is, it d

 Enter any string from the keyboard ( Can contain ： Letter 、 Numbers 、 Punctuation , And space characters ), Calculate the actual number of characters and print out , That is, do not use string handlers strlen() Programming , But it can be achieved strlen() The function of .
 Program running example ：
Please enter a string:how are you
The length of the string is: 11
 The procedure is as follows , The horizontal line represents the missing source code , Please add the missing part , And fill in the complete program code in the answer area .

#include  <stdio.h>
___________ /*   Function declaration   */
int main()
{
	char   a[80];
	unsigned int  len;
	printf("Please enter a string:");
	___________   /*    Input string    */
	 ___________      /*  Call function , Calculate the actual number of characters in the string  */
	printf("The length of the string is: %u\n", len); 
	return 0;
}

/*  The functionality ： Use character pointer as function parameter , Calculate the length of the string  */
unsigned int  MyStrlen(char *pStr)
{ 
	___________      /*  Declare count variables  */
	for ( ______ ;_______  ;________)       /*  Cycle control conditions   */
	{
		len++;                 /*  Statistics do not include '\0' Number of characters included  
	}
	        ___________       /*  Returns the actual number of characters  */
}

The answer is as follows ：

#include  <stdio.h>
unsigned int  MyStrlen(char *pStr);      
int main()
{	    	 	  	   
	char   a[80];
	unsigned int  len;
	printf("Please enter a string:");
	gets(a);                  
	len = MyStrlen(a);      
	printf("The length of the string is: %u\n", len); 
	return 0;
}	    	 	  	   
/*  The functionality ： Use character pointer as function parameter , Calculate the length of the string  */
unsigned int  MyStrlen(char *pStr)
{ 
	unsigned int  len = 0;   
	for ( ; *pStr!='\0'; pStr++)   
	{	    	 	  	  
		len++;                 
	}
	return (len);           
}