Basic methods of realizing licensing function in C language

   Hello everyone !

  Today I would like to talk with you , How to use it C Language implementation of automatic licensing program .

First of all ： Problem description

    A deck of poker has 52 card , When you play bridge, you should give the cards to 4 personal . Please design a program to complete the automatic licensing work . requirement ： For spades S (Spaces) Express , For hearts H (Hearts) Express , Square with D (Diamonds) Express , Plum blossom with C (Clubs) Express .

second ： Problem analysis

Ideas :

This problem is relatively simple to realize , Just define two multidimensional character arrays , The first number used to store poker , The second is for storing 4 A player's hand .

52 A card is given to 4 personal , Need to send 13 round , Each round deals cards to players in the order of their numbers , When licensing , Generate the number to be dealt with a random function （ For the introduction of random functions, please refer to my chapter 61 Days of practice ）, If the card has not been issued before （ The issued cards are used for '\0' Mark ）, Then the card number is stored in the player's hand array , At the same time, assign the number of the card to '\0'. If the card corresponding to the generated random number has been dealt , Then continue to generate new random numbers . When 52 All cards have been issued , Print the result of the deal .

Poker array char poker[4][13]; Medium 4 There are four kinds of designs and colors ,13 Indicates that each has 13 Zhang （13 Number ）, The number of playing cards （ name ） To express in characters , Respectively ：{'2', '3', '4', '5', '6', '7', '8', '9', '0', 'J', 'Q', 'K', 'A'}（'0' Express 10）

The player's hand array is a three-dimensional character array ,char players[PLAYER_NUMBER][4][13] = {0}; （PLAYER_NUMBER It's the number of players ,4 The colors and types of the sign are 4 Kind of ,13 The most cards for a suit 13 Zhang ）

On initialization , All values of the hand array are set to '\0', No card on hand .

Third ： Code implementation

 

 

 

Fourth ： Running results

  summary ： Only practice more , In the process of practicing , Find the problem points, solve them one by one and summarize , To go further .

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