Implementation of remove function

alas , A low-level mistake , An equal sign is missing , Logical judgment becomes an assignment

// Implementation function void remove(char* str1, char* str2).
// function ： take str2 The characters appearing in are from str1 Remove from .（ for example str1 by ”abcdef”, str2 by ”bde”, After removal str1 Turn into ”acf”.
void remove(char* str1, char* str2)
{
	if((!str1) || (!str2)) return ;


	char *tmp = (char *)malloc(strlen(str1)+1);
	if(!tmp) return ;
	
	int i, j;
	int m = 0;
	for(i=0; i< strlen(str1); i++)
	{
		int k = 0;
		for(j = 0; j < strlen(str2); j++)
		{
			if(str1[i] == str2[j]) k++;
		}

		if(k == 0)
		{
			tmp[m++] = str1[i];
		}
	}

	memcpy(str1, tmp, m);
	str1[m] = '\0';
	
	free(tmp);
	tmp = NULL;
	
	return;
}

The first time I wrote it , hold