Daily question 3 (2): check binary string field

subject ：

Give you a binary string s , The string Without leading zeros .

If s contain Zero or one by continuous ‘1’ The fields made up of , return true​​​ . otherwise , return false .

Example 1：

Input ：s = “1001”
Output ：false
explain ： In the string 1 Not forming a continuous field .
Example 2：

Input ：s = “110”
Output ：true

Tips ：

1 <= s.length <= 100
s[i]​​​​ by ‘0’ or ‘1’
s[0] by ‘1’

Ideas ：

The meaning of this question is not easy to understand , Actually, I want to check whether the string contains ’01’, It is suggested to have a look at this question , Omission as an important topic

java Code ：

class Solution {
    public boolean checkOnesSegment(String s) {
return !s.contains("01");
    }
}