1640. Can you connect to form an array -c language implementation

1640. Can you join to form an array -c Language implementation

Give you an array of integers arr , Every integer in the array Different from each other . There's another array of integers pieces, The integers are also Different from each other . Please use In any order Connect pieces In order to form arr . however , Don't allow For each array pieces[i] Reorder integers in .

If you can connect pieces The array in the form of arr , return true ; otherwise , return false .

Example 1：

Input ：arr = [15,88], pieces = [[88],[15]]
Output ：true
explain ： Connect in turn [15] and [88]

Example 2：

Input ：arr = [49,18,16], pieces = [[16,18,49]]
Output ：false
explain ： Even if the numbers match , You can't rearrange pieces[0]

Example 3：

Input ：arr = [91,4,64,78], pieces = [[78],[4,64],[91]]
Output ：true
explain ： Connect in turn [91]、[4,64] and [78]

Personally, I think this question should have been very difficult ,leedcode in c There are few problems in language , The solution code is as follows , The code intensity is still very high ：

bool canFormArray(int* arr, int arrSize, int** pieces, int piecesSize, int* piecesColSize){
    
    int r[piecesSize];
    int i;
    for(i=0;i<piecesSize;i++){
    
        r[i]=1;
    }
    for(i=0;i<arrSize;i++){
    
        int rz=0;
       
        for(int k=0;k<piecesSize;k++){
    
             int j=i;
           
            if(r[k]==1&&pieces[k][0]==arr[j]){
    
                int p;
                
                for( p=1;p<piecesColSize[k];p++){
    
                    if(pieces[k][p]!=arr[++j]){
    
                        break;
                    }
                }
                if(p==piecesColSize[k]){
    
                    r[k]=0;
                    i=j;
                    rz=1;
                    break;
                }
                
            }
        }
        if(rz==0){
    
            return false;
        }
    }
    return true;

}