Niuke brush sql---2

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 SQL37  Sort multiple columns after searching

describe

subject ： Now the operator wants to take out the age and... In the user information table gpa data , And first according to gpa Ascending sort , Then sort the output in ascending order of age , Please take out the corresponding data .

User information sheet ：user_profile

id	device_id	gender	age	university	gpa
1	2138	male	21	Peking University,	3.4
2	3214	male	23	Fudan University	4
3	6543	female	20	Peking University,	3.2
4	2315	female	23	Zhejiang University	3.6
5	5432	male	25	Shandong University	3.8
6	2131	male	28	Beijing Normal University	3.3

Your query should return the following results ：

device_id	gpa	age
6534	3.2	20
2131	3.3	28
2138	3.4	21
2315	3.6	23
5432	3.8	25
3214	4	23

Example 1

Input ：

drop table if exists user_profile;
CREATE TABLE `user_profile` (
`id` int NOT NULL,
`device_id` int NOT NULL,
`gender` varchar(14) NOT NULL,
`age` int ,
`university` varchar(32) NOT NULL,
`gpa` float);
INSERT INTO user_profile VALUES(1,2138,'male',21,' Peking University, ',3.4);
INSERT INTO user_profile VALUES(2,3214,'male',23,' Fudan University ',4.0);
INSERT INTO user_profile VALUES(3,6543,'female',20,' Peking University, ',3.2);
INSERT INTO user_profile VALUES(4,2315,'female',23,' Zhejiang University ',3.6);
INSERT INTO user_profile VALUES(5,5432,'male',25,' Shandong University ',3.8);
INSERT INTO user_profile VALUES(6,2131,'male',28,' Beijing Normal University ',3.3);

Copy output ：

6543|3.200|20
2131|3.300|28
2138|3.400|21
2315|3.600|23
5432|3.800|25
3214|4.000|23

select device_id,gpa,age from  user_profile order by gpa ,age;

SQL38  Sort in descending order after finding

describe

subject ： Now the operator wants to retrieve the corresponding data in the user information table , And first according to gpa、 Sort the output in descending order of age , Please take out the corresponding data .

Example  user_profile：

id	device_id	gender	age	university	gpa
1	2138	male	21	Peking University,	3.4
2	3214	male	23	Fudan University	4
3	6543	female	20	Peking University,	3.2
4	2315	female	23	Zhejiang University	3.6
5	5432	male	25	Shandong University	3.8
6	2131	male	28	Beijing Normal University	3.3

According to the example , Your query should return the following results ：

device_id	gpa	age
3214	4	23
5432	3.8	25
2315	3.6	23
2138	3.4	21
2131	3.3	28
6543	3.2	20

Example 1

Input ：

drop table if exists user_profile;
CREATE TABLE `user_profile` (
`id` int NOT NULL,
`device_id` int NOT NULL,
`gender` varchar(14) NOT NULL,
`age` int ,
`university` varchar(32) NOT NULL,
`gpa` float);
INSERT INTO user_profile VALUES(1,2138,'male',21,' Peking University, ',3.4);
INSERT INTO user_profile VALUES(2,3214,'male',23,' Fudan University ',4.0);
INSERT INTO user_profile VALUES(3,6543,'female',20,' Peking University, ',3.2);
INSERT INTO user_profile VALUES(4,2315,'female',23,' Zhejiang University ',3.6);
INSERT INTO user_profile VALUES(5,5432,'male',25,' Shandong University ',3.8);
INSERT INTO user_profile VALUES(6,2131,'male',28,' Beijing Normal University ',3.3);

Copy output ：

3214|4.0|23
5432|3.8|25
2315|3.6|23
2138|3.4|21
2131|3.3|28
6543|3.2|20

select device_id, gpa, age from user_profile order by gpa desc,age desc  ;

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