Sqlserver gets the data of numbers, Chinese and characters in the string

-- Get English character data

Create function [dbo].[Fun_GetChar]
(
@No varchar(100)
)
RETURNS varchar(100)
AS
BEGIN
WHILE PATINDEX('%[^A-Za-z]%',@No)>0
BEGIN
SET @No=STUFF(@No,PATINDEX('%[^A-Za-z]%',@No),1,'') 
END
RETURN CONVERT(varchar(100),@No)
END

--select dbo.F_GetChar('2.5mg')-- Call function =mg
 

-- Get numeric data

Create FUNCTION [dbo].[Fun_GetNum] 
( @Str NVARCHAR(MAX) )
RETURNS NVARCHAR(MAX)
AS
    BEGIN
        DECLARE @Start INT;
        DECLARE @End INT; 
        DECLARE @Part NVARCHAR(MAX)
        SET @Start = PATINDEX('%[.,0-9]%', @Str);
        SET @End = PATINDEX('%[.,0-9]%',SUBSTRING(@Str, @Start+1,LEN(@Str) - @Start));
        SET @Part = SUBSTRING(@Str,@Start,1) 
        WHILE  @End >0 
        BEGIN 
                SET @Start = @[email protected]
                SET @Part = @Part+SUBSTRING(@Str,@Start,1)       
                SET @End = PATINDEX('%[0-9]%',SUBSTRING(@Str, @Start+1,LEN(@Str) - @Start)); 
        END
            
        RETURN  @Part;
    END;

--seleect dbo.[Fun_GetNumPart]('2.5mg')-- Call function =2.5

-- Get Chinese data

create function [dbo].[Fun_getCN]
(@str varchar(4000)) 
returns varchar(4000) 
as 
begin 
declare @word nchar(1),@CN varchar(4000) 
set @CN='' 
while len(@str)>0 
begin 
set @word=left(@str,1) 
if unicode(@word) between 19968 and 40869 
set @[email protected][email protected] 
set @str=right(@str,len(@str)-1) 
end 
return @CN 
end 
GO 

--select dbo.[Fun_getCN('2.5mg, mg ')-- Call function = mg