Title 37: sorting 10 numbers

In the first solution , I'll arrange the data first , Reverse the line again , Because there are few sorted data at present , So there is no problem with this operation .

however , In fact, sorting is a waste of time . More economical , You can first store the results of the positive row in an array , Then reverse output it , You can get the inverted data . This operation is twice as fast as the first solution , save 50% Time for .

Code ：

number_list = []
for i in range(1, 11):
    number_i = int(input(f' Please enter the first {i} Number ：'))
    number_list.append(number_i)
number_list.sort()
print(f' The order from small to large is ：{number_list}')
number_list.reverse()
print(f' The order from big to small is ：{number_list}')

Running results ：