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std::memory_order_seq_cst内存序

2022-06-27 09:11:00 wangzai6378

一、在多生产者与多消费者的情况

#include <thread>
#include <atomic>
#include <cassert>
 
std::atomic<bool> x = {false};
std::atomic<bool> y = {false};
std::atomic<int> z = {0};
 
void write_x()
{
    x.store(true, std::memory_order_seq_cst);
}
 
void write_y()
{
    y.store(true, std::memory_order_seq_cst);
}
 
void read_x_then_y()
{
    while (!x.load(std::memory_order_seq_cst))
        ;
    if (y.load(std::memory_order_seq_cst)) {
        ++z;
    }
}
 
void read_y_then_x()
{
    while (!y.load(std::memory_order_seq_cst))
        ;
    if (x.load(std::memory_order_seq_cst)) {
        ++z;
    }
}
 
int main()
{
    std::thread a(write_x);
    std::thread b(write_y);
    std::thread c(read_x_then_y);
    std::thread d(read_y_then_x);
    a.join(); b.join(); c.join(); d.join();
    assert(z.load() != 0);  // will never happen
}

        线程a和b是生产者,线程c和d是消费者。所有的生产者(a和b)会发生内存排序;所有的消费者(c和d)在消费时,都是以生产都排好的内存序来执行代码。所以,这里c和d观察a和b时,要么是先x变为true,然后y变为true;要么是先y变为true,再x变为true。无论哪种情况至少为1。

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https://blog.csdn.net/wanghualin033/article/details/125328402