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Hangzhou Electric School Competition (Counter Attack Index)
2022-08-04 14:36:00 【51CTO】
逆袭指数
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 1854 Accepted Submission(s): 374
Problem Description
这依然是关于高富帅小明曾经的故事—— 尽管身处逆境,但小明一直没有放弃努力,除了搬砖,小明还研究过东方的八卦以及西方的星座,I have been trying to find the basis for my counterattack in numerology. When all of these fail,Xiao Ming turned to mathematical research,Hope to get some information from it.一天,Xiao Ming is researching《BestCoderThe mathematical basis of counterattack》这本书时,Found valuable information,其中写道: Everyone has a counterattack index,For this counterattack index,There may be continuous factors,If this continuous factor is long enough,Then the probability of this person counterattack is very high! Xiao Ming knew his counterattack index,Please tell Xiao Ming his longest continuous factor,Let him judge whether he can counterattack himself.
Input
输入包含多组测试数据. 每组数据占一行,包含一个整数N,Indicates Xiao Ming's counterattack index,N小于2^31.
Output
对于每组数据,请输出2行: The first line outputs the longest number of factors; The second line outputs the smallest sequence of factors,Please refer to the example for details. 特别说明:Because Xiao Ming hates being single very much,所以1Not a factor.
Sample Input
630
12
Sample Output
Hint
630 = 3*5*6*7
思路:It's hard to look at,After reading the blog of the great god, I realized how much I have,God's address:http://www.1or1.xyz/?p=182
AC代码:
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