Parameter index out of range (1 > number of parameters, which is 0)

Here is the error message

select * from user where uid  like '%?%'
java.sql.SQLException: Parameter index out of range (1 > number of parameters, which is 0).
	at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:1055)
	at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:956)
	at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:926)
	at com.mysql.jdbc.PreparedStatement.checkBounds(PreparedStatement.java:3288)
	at com.mysql.jdbc.PreparedStatement.setInternal(PreparedStatement.java:3272)
	at com.mysql.jdbc.PreparedStatement.setInternal(PreparedStatement.java:3314)
	at com.mysql.jdbc.PreparedStatement.setInt(PreparedStatement.java:3258)
	at com.mysql.jdbc.PreparedStatement.setObject(PreparedStatement.java:3533)
	

Possible errors in precompiled assignment ：

1. The specified assignment position is wrong , namely parameterIndex Parameter error , The value of this parameter is from 1 Start
2. The number of assignments is not enough

Guarantee sql There is no mistake in the statement , And use precompiled assignment without error ：
…
It could be sql The character splicing method used in the statement is incorrect , This is what Xiaobian is like , The above-mentioned exception occurs when using single quotation marks at the beginning .

resolvent ：
change sql The splicing of statements , Xiaobian changed to
select * from user where uid like concat('%',?,'%')