Daily question 1 - force deduction - there are three consecutive arrays of odd numbers

The title comes from Li Kou ——1550. There are three consecutive odd arrays - Power button （LeetCode） (leetcode-cn.com)

Give you an array of integers arr, Please judge whether three consecutive elements in the array are odd ： If there is , Please return true ; otherwise , return false .

Example 1：

Input ：arr = [2,6,4,1]
Output ：false
explain ： There is no case where three consecutive elements are odd .
Example 2：

Input ：arr = [1,2,34,3,4,5,7,23,12]
Output ：true
explain ： There is a case where three consecutive elements are odd , namely [5,7,23] .

bool threeConsecutiveOdds(int* arr, int arrSize){
    int i = 0;
    int count = 0;
    for(i=0;i<arrSize;i++)
    {
        if(arr[i] %2 !=0)
        {
            count++;
            if(count == 3)
            {
                break;
            }
        }
        else
        {
            count = 0;
        }
    }
    if(count == 3)
    {
        return true;
    }
    else
    {
        return false;
    }
}