Force deduction exercise -- deleting repeated items in ordered sequence 1.0

Ideas for solving this problem ： Yes, it is result This variable is used to record several different elements
Then loop through the array , Whether the elements of the current index and the next index are consistent , To determine how many different elements there are
however ,result It also indicates the actual position of this different element in the array . This is my personal language explanation ,
The explanation may not be very clear , You can understand it by looking at the code , Welcome comments if you don't understand . You are also welcome to give us some advice .

class Solution {
    
    public int removeDuplicates(int[] nums) {
    
        //  Judge whether it is empty first , If it is blank, it can be directly output as 0
        if (nums.length == 0) return 0;
        //  Define a variable to record a total of several distinct data 
        int result = 1;
        //  If the array length is 1 It can also be output directly 
        if (nums.length == 1) return result;
        //  Traverse... With a loop nums Array 
        for (int i = 0; i < nums.length-1; i++) {
    
            /*  Judge here   Current nums Of the i Array elements   And the next array   Whether the elements are consistent , That is the first. i+1 Elements , If consistent, enter if Statement Libiao  */
            if (nums[i] != nums[i+1]) {
    
                /*  here result It records that there are several different data in the array , At the same time, it can also indicate where the next element and the previous element should be located   At this time, you only need to assign the next data in the array to nums Array of result Location is OK  */
                nums[result] = nums[i+1];
                result++;
            }
        }
        return result;
    }
}