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[digital signal processing] correlation function (finite signal | autocorrelation function of finite signal)
2022-06-12 02:34:00 【Hanshuliang】
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One 、 Autocorrelation function of finite signal
about " Limited signal " x ( n ) x(n) x(n) , n n n The range of phi is zero [ 0 , N − 1 ] [0, N-1] [0,N−1] Closed interval ;
be Limited signal x ( n ) x(n) x(n) Of Autocorrelation function yes :
r x ( m ) = 1 N ∑ n = 0 N − 1 − m x ∗ ( n ) x ( n + m ) r_x(m) = \cfrac{1}{N}\sum_{n = 0}^{N-1-m}x^*(n)x(n+m) rx(m)=N1n=0∑N−1−mx∗(n)x(n+m)
∑ n = 0 N − 1 − m x ∗ ( n ) x ( n + m ) \sum_{n = 0}^{N-1-m}x^*(n)x(n+m) ∑n=0N−1−mx∗(n)x(n+m) Divide N N N Equivalent to the m m m by 0 0 0 when , The value of the autocorrelation function is signal power ;
r x ( 0 ) = Letter Number work rate r_x(0) = signal power rx(0)= Letter Number work rate
seek mean value or variance , Both need to work with N N N be divided by , N N N Is time , That is, the number of finite signals , Here is the Yes Time Averaging ;
Limited signal yes Energy signal , " Autocorrelation function " Of " The Fourier transform " yes " Power spectral density function " ,
Limited signal Of Time n n n Value range of yes [ 0 , N − 1 ] [0, N-1] [0,N−1] Closed interval , But in the formula Additive formula yes
∑ n = 0 N − 1 − m \sum_{n = 0}^{N-1-m} n=0∑N−1−m
No
∑ n = 0 N − 1 \sum_{n = 0}^{N-1} n=0∑N−1
Because it's for x ( n ) x(n) x(n) And x ( n + m ) x(n+m) x(n+m) The correlation function of ;
If The signal displacement m m m , Beyond the n n n Value range of [ 0 , N − 1 ] [0, N-1] [0,N−1] Closed interval , This signal is not the original signal , The autocorrelation function is meaningless ;
So here's n n n Value , Must be [ 0 , N − 1 − m ] [0, N-1-m] [0,N−1−m] Closed interval ;
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