Blue Bridge Cup basic-15 VIP question string comparison

test questions Based on practice String comparison

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Resource constraints

The time limit ：1.0s   Memory limit ：512.0MB

Problem description

　　 Given two strings consisting of only uppercase or lowercase letters ( Length between 1 To 10 Between ), The relationship between them is as follows 4 One of the situations in ：
　　1： Two strings are not the same length . such as Beijing and Hebei
　　2： Two strings are not only equal in length , And the characters in the corresponding positions are exactly the same ( Case sensitive ), such as Beijing and Beijing
　　3： Two strings are equal in length , The characters in the corresponding positions can be completely consistent only if they are not case sensitive （ in other words , It's not satisfied with the situation 2）. such as beijing and BEIjing
　　4： Two strings are equal in length , But even case insensitive doesn't make the two strings consistent . such as Beijing and Nanjing
　　 Programming determines which of these four categories is the relationship between the two input strings , Give the number of the class .

Input format

　　 It includes two lines , Each line is a string

Output format

　　 There is only one number , Indicates the relationship number of these two strings

The sample input

BEIjing

beiJing 

Sample output

3

The solution is as follows --

import java.util.Scanner;

public class Main {

    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        String str1 = scanner.next();
        String str2 = scanner.next();
        
        if (str1.length() != str2.length()) {            //1： Two strings are not the same length .
            System.out.println(1);
        } else {
            if (str1.equals(str2)) {                    //2： Two strings are not only equal in length , And the characters in the corresponding positions are exactly the same ( Case sensitive )
                System.out.println(2);
            }else if (str1.equalsIgnoreCase(str2)) {    //3： Two strings are equal in length , The characters in the corresponding positions can be completely consistent only if they are not case sensitive
                System.out.println(3);
            }else {                                        //4： Two strings are equal in length , But even case insensitive doesn't make the two strings consistent .
                System.out.println(4);
            }
        }
    }
}

The demonstration effect is as follows --

I hope this article can help you ！

Thank you. ！