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The influence of the number of non-zero values in the picture on Classification
2022-07-27 10:58:00 【Black elm】
( 0 , 7)---m*n*2---(1,0)(0,1)
take mnist The picture of is reduced to 9*9, Statistics of non 0 Number of points
0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 |
44.4698 | 27.7134 | 41.7294 | 17.9278 | 15.9034 | 16.9892 | 17.8176 | 14.0056 | 19.4652 | 15.9438 |
It turns out that 0 At most non 0 spot , The average is about 44.5 individual . and 7 least , stay 81 Only about 14 Values are non-zero . Now change the form 7 Compare the number of zeros in Central Africa and how the number of iterations changes .
0*7 | |||||||||
f2[0] | f2[1] | The number of iterations n | Average accuracy p-ave | 1-0 | 0-1 | δ | Time consuming ms/ Time | Time consuming ms/199 Time | |
44.4698-14.0056 | 8.55E-06 | 0.999991 | 7822.01 | 0.992943 | 0.995795 | 0.990223 | 1.00E-05 | 270.7437 | 53889 |
44.4698-14.0056*0.9 | 8.43E-06 | 0.999992 | 5539.92 | 0.989532 | 0.989457 | 0.989603 | 1.00E-05 | 174.8241 | 34797 |
44.4698-14.0056*0.8 | 7.11E-06 | 0.999993 | 4698.231 | 0.984982 | 0.980028 | 0.989705 | 1.00E-05 | 169.3769 | 33842 |
44.4698-14.0056*0.7 | 8.02E-06 | 0.999992 | 5672.623 | 0.99049 | 0.985627 | 0.995126 | 1.00E-05 | 184.3367 | 36689 |
44.4698-14.0056*0.6 | 6.43E-06 | 0.999994 | 4257.085 | 0.991707 | 0.991888 | 0.991534 | 1.00E-05 | 156.2965 | 31117 |
44.4698-14.0056*0.5 | 6.36E-06 | 0.999994 | 5994.452 | 0.994202 | 0.994862 | 0.993572 | 1.00E-05 | 197.5276 | 39319 |
44.4698-14.0056*0.4 | 8.39E-06 | 0.999992 | 8845.538 | 0.995017 | 0.995929 | 0.994149 | 1.00E-05 | 260.4221 | 51840 |
44.4698-14.0056*0.3 | 9.09E-06 | 0.999991 | 15703.26 | 0.998956 | 0.997862 | 1 | 1.00E-05 | 447.2864 | 89020 |
44.4698-14.0056*0.2 | 8.97E-06 | 0.999991 | 28967.59 | 0.99965 | 1 | 0.999316 | 1.00E-05 | 895.5377 | 178223 |
For example, the last set of data 44.4698-14.0056*0.2 indicate , form 7 Only randomly reserved 20% Non - 0 spot , It's just 2-3 There are white dots, and the rest are all black . Experimental results show that even so, the network can achieve convergence , And the classification accuracy is all 10 The highest in the Group .
Compare the number of iterations

The number of iterations decreases first and then increases , The lowest point is about 60%. According to the inverse relationship between the number of iterations and entropy

It shows that the entropy of these two groups of pictures increases first and then decreases .
With non 0 The decrease of value and the decrease of entropy are well explained , But how to explain 60% before , With non 0 The phenomenon of decreasing value and increasing entropy ? Because it's white on black , So the difference between the two groups of pictures should be 4 Kind of
0 | white | 7 | white |
0 | white | 7 | black |
0 | black | 7 | black |
0 | black | 7 | white |
It should be this 4 These differences jointly determine the result of classification , If 7 White dots decrease , Then the black dot increases ,
0 | white | 7 | white | Reduce |
0 | black | 7 | white | Reduce |
form 0 relative 7 The difference in white should be smaller , It becomes less obvious . and
0 | white | 7 | black | increase |
0 | black | 7 | black | increase |
relative 7 The difference in the black part of should be bigger .
So with 7 Decrease of white dot , Just assume that 60% The former difference increases more than the former difference decreases , And in the 60% In the future, the increase of the difference is less than the decrease of the difference , It can explain the inflection point of the curve .
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