Use js to count the number of occurrences of each string in the string array, and format it into an object array.

1. demand

• The original array ：

[‘ Steamed stuffed bun ’, ‘ Steamed bread ’, ‘ Hanamaki ’, ‘ Steamed Bun Stuffed with Juicy Pork ’, ‘ Steamed bread ’]

• Format it as ：

[
{ name: ‘ Steamed stuffed bun ’, value: 1 },
{ name: ‘ Steamed bread ’, value: 2 },
{ name: ‘ Hanamaki ’, value: 1 },
{ name: ‘ Steamed Bun Stuffed with Juicy Pork ’, value: 1 }
]

2. Realization

2.1 Statistics string array , The number of occurrences of each string , Form hash table

let arr = [" Steamed stuffed bun ", " Steamed bread ", " Hanamaki ", " Steamed Bun Stuffed with Juicy Pork ", " Steamed bread "];
let map = {
    };
//  Traverse list data 
for (let i = 0; i < arr.length; i++) {
    
  var name = arr[i];
  if (map[name]) {
    
    map[name] += 1;
  } else {
    
    map[name] = 1;
  }
}
console.log(map);

result ：

2.2 Traversal hash table , Format it

let resList = [];
//  Traverse hash surface 
for (let name in map) {
    
  let item = {
    };
  item["name"] = name;
  item["value"] = map[name];
  resList.push(item);
}
console.log(resList);

result ：

3. Complete code

let arr = [" Steamed stuffed bun ", " Steamed bread ", " Hanamaki ", " Steamed Bun Stuffed with Juicy Pork ", " Steamed bread "];
let map = {
    };
//  Traverse list data 
for (let i = 0; i < arr.length; i++) {
    
  var name = arr[i];
  if (map[name]) {
    
    map[name] += 1;
  } else {
    
    map[name] = 1;
  }
}
console.log(map);
let resList = [];
//  Traverse hash surface 
for (let name in map) {
    
  let item = {
    };
  item["name"] = name;
  item["value"] = map[name];
  resList.push(item);
}
console.log(resList);